Answer: The variable that you change in an experiment
Explanation: It does not rely on any other factors that deal with the experiment
Answer:
The work done by the gas expansion is 5875 J,
Since the work done is positive, the work is done by the gas on the surroundings.
Explanation:
Given;
change in internal energy, ΔU = -4750 J
heat transferred to the system, Q = 1125 J
The change in internal energy is given by;
ΔU = Q - W
Where;
W is the work done by the system
The work done by the system is calculated as;
W = Q - ΔU
W = 1125 - (-4750)
W = 1125 + 4750
W = 5875 J
Since the work done is positive, the work is done by the gas on the surroundings (energy flows from the gas to the surroundings).
Therefore, the work done by the gas expansion is 5875 J
Answer:
concentration of
= 0.0124 = 12.4 ×10⁻³ M
concentration of
= 0.0248 = 2.48 ×10⁻² M
concentration of
= 0.4442 M
Explanation:
Equation for the reaction:
⇄
+ 
Concentration of
=
= 0.469
For our ICE Table; we have:
⇄
+ 
Initial 0.469 0 0
Change - 2x +2x +x
Equilibrium (0.469-2x) 2x x
K = ![\frac{[CO]^2[O]}{[CO_2]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO%5D%5E2%5BO%5D%7D%7B%5BCO_2%5D%5E2%7D)
K = ![\frac{[2x]^2[x]}{[0.469-2x]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2x%5D%5E2%5Bx%5D%7D%7B%5B0.469-2x%5D%5E2%7D)

Since the value pf K is very small, only little small of reactant goes into product; so (0.469-2x)² = (0.469)²




![x=\sqrt[3]{1.9929*10^{-6}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B1.9929%2A10%5E%7B-6%7D%7D)
x = 0.0124
∴ at equilibrium; concentration of
= 0.0124 = 12.4 ×10⁻³ M
concentration of
= 2x = 2 ( 0.0124)
= 0.0248
= 2.48 ×10⁻² M
concentration of
= 0.469-2x
= 0.469-2(0.0124)
= 0.469 - 0.0248
= 0.4442 M
<u>Answer:</u>
The temperature of the water is 70°C
<u>Explanation:</u>
Partial pressure of helium gas = 526 mmHg
Total pressure inside the jar= 760 mmHg
Suppose partial pressure of helium gas is
and partial pressure of water is
And total pressure is 
As we know

Hence
Putting the values



In bar,

= 0.312 bar
Now according to the steam table
With the vapour pressure of water as 0.312 bar the temperature corresponds to 70°C