How many grams of aluminum can be heated from 94.2°C to 120.5°C if 593.0 joules are applied? The specific heat of aluminum is 0.
1 answer:
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Answer:
POINTS OF INTERSECTION ARE:
x = -1
y = 3
coordinates : (-1,3)
Coordinates :
Explanation:
Condition for intersecting lines
here
a1 ,a2 = coefficients of x (a1 = -1 , a2 = 6)
b1 ,b2 = coefficients of y(b1 = 1 , b2 = 1)
Calculation :
Here substitution method is used : Value of y from eq (1) is substitued in equation (2)
-x + y = 4
y = 4 + x.............(i)
put value of x in equation (2)
6x + y = -3
6x + 4 + x = -3 ( from i)
7x = -3 - 4
7x = -7
x =
x = -1
using equation(i)
y = 4 + (-1)
y = 4 - 1
y = 3
Check:
The values of x and y should satisfy equation (1) and (2)
for equation 1
-x+y =4
= -(-1) + 3
= 1 + 3
= 4
Hence coordinates satisfy equation 1