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WITCHER [35]
2 years ago
12

What is the importance of a special habitat?

Chemistry
1 answer:
vfiekz [6]2 years ago
8 0
They meet all the environmental conditions an organism needs to survive
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HELP PLS<br> kakwkwkwkkwkwkw
Vanyuwa [196]

Answer:

yo try and search it on Google

4 0
4 years ago
3. A reaction produces 14.2 grams of a product. The theoretical yield of that product
nlexa [21]

A reaction that produces 14.2 grams of a product and the theoretical yield of that product is 17.1 grams is true for the following statements :

The percent yield of the product is 83.0%

The actual yield of the product is 14.2 grams.

<h3>Percentage Yield:</h3>

Percent yield is the percent ratio of actual yield to the theoretical yield.

Mathematically,

percent yield = actual yield / theoretical yield x 100%

actual yield = 14.2 grams

theoretical yield = 17.1 grams

percentage yield = 14.2 / 17.1 × 100%

percentage yield = 83.0409356725 %

percentage yield = 83.0 %

Therefore,

The percent yield of the product is 83.0%

The actual yield of the product is 14.2 grams.

learn more on percentage yield here; brainly.com/question/4180677

3 0
3 years ago
What is a supersaturated solution?
oee [108]

Answer:

A supersaturated solution is a more solute solution than can be dissolved by the solvent.

Explanation:

sodium acetate is an example of one

3 0
2 years ago
I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
3 years ago
Write the symbol for every chemical element that has an atomic number less than 13 and atomic mass greater than 19.3 u
emmainna [20.7K]

Answer:

The symbol of each element is, Ne, Na, Mg, and Al.

Explanation:

Below is the list of elements that has an atomic mass of less than 19.3 u.

The atomic mass of Neon is 20.1797 u and the atomic number is 10.

The atomic mass of Sodium is 22.989769 u and the atomic number is 11.

The atomic mass of Magnesium is 24.305 u and the atomic number is 12.

The atomic mass of Aluminium is 26.981539 u and the atomic number is 13.

Here, the symbol of each element is, Ne, Na, Mg, and Al.

3 0
3 years ago
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