1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olchik [2.2K]
3 years ago
10

A 2.5 g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tre

e's trunk. What is the initial kinetic energy of the bullet? 153.125 J Correct: Your answer is correct. How much work does the tree do in stopping the bullet?
Physics
2 answers:
Luden [163]3 years ago
6 0

Answer:

The work done by the tree in stopping the bullet is 0.00294 J

Explanation:

To determine how much work done by the tree in stopping the bullet, we first determine the force of the bullet.

Force = mass x acceleration due to gravity

Force = 0.0025 x 9.8 = 0.0245 N

Work done = Force x distance

                  = 0.0245 x 0.12

                  = 0.00294 J

Therefore, the work done by the tree in stopping the bullet is 0.00294 J

Cloud [144]3 years ago
4 0

Answer: Work done = 153.125Joules, Work done = 0.003Nm

Explanation:

Kinetic energy of a body is the energy possessed by a body by virtue of its motion.

Mathematically,

K.E = 1/2MV²

Where;

M = mass of the body = 2.5g = 0.0025kg

V = velocity of the body = 350m/s

Substituting this values in the formula, we have;

K.E = 1/2× 0.0025×350²

K.E = 153.125Joules

Work done is the force applied to body to cause it to move through a distance.

Work = Force × distance

Force = ma = 0.0025 × 10

Force = 0.025N

Distance = 12cm = 0.12m

Work = 0.025×0.12

Work = 0.003Nm

work done by the tree in stopping the bullet is 0.003N

You might be interested in
A student throws a 140 g snowball at 6.5 m/s at the side of the schoolhouse, where it hits and sticks. What is the magnitude of
Vitek1552 [10]

Answer:5.35N

Explanation:

Force is defined as the product of mass of an object and its acceleration.

Acceleration is the change in velocity of an object with respect to time.

Acceleration = velocity/ time = 6.5/0.17 = 38.2m/s²

since F = ma and mass is 140g

140g to kg will be 140/1000 = 0.14kg

F = 0.14× 38.2

F = 5.35N

magnitude of the average force is 5.35N

3 0
3 years ago
A singly charged ion (q=−1.6×10−19) makes 7.0 rev in a 45 mT magnetic field in 1.29 ms. The mass of the ion in kg is
insens350 [35]

Answer:

m=1.47\times 10^{-24}\ Kg

Explanation:

Given that,

Charge, q=1.6\times 10^{-19}\ C

Revolution = 7 rev

magnetic field, B = 45 mT

Time, t = 1.29 ms

We need to find the mass of the ion. Let m be the mass. The formula for the mass in terms of time period is given by :

m=\dfrac{qBT}{2\pi}\\\\m=\dfrac{1.6\times 10^{-19}\times 45\times 10^{-3}\times 1.29\times 10^{-3}}{2\pi}\\\\m=1.47\times 10^{-24}\ Kg

So, the mass of the ion is equal to 1.47\times 10^{-24}\ Kg.

4 0
3 years ago
Two objects were lifted by a machine. One object had a mass of 5000 kg, and was lifted at a speed of 2 m/sec. The other had a ma
Leokris [45]
Equation for ke = 1/2mv^2
1) ke = 1/2 x 5000 x (2x2)
= 10,000J
2) ke = 1/2 x 4000 x (3x3)
= 18,000J
So Object 2 has more Kinetic Energy
3 0
3 years ago
Write one example situation of Newton's Third Law involving mass that are the same.
puteri [66]

Answer:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

6 0
3 years ago
a student drops an object from the top of a building which is 19.6 m high. How long does it take the object to fall to the groun
zubka84 [21]

Here's a formula that's simple and useful, and if you're really in
high school physics, I'd be surprised if you haven't see it before. 
This one is so simple and useful that I'd suggest memorizing it,
so it's always in your toolbox.

This formula tells how far an object travels in how much time,
when it's accelerating:

               Distance = (1/2 acceleration) x (Time²).

                           D = 1/2 A T²

For your student who dropped an object out of the window,

     Distance = 19.6 m
     Acceleration = gravity = 9.8 m/s²

                                              D = 1/2 G T²

                                          19.6 =   4.9   T²

Divide each side by 4.9 :       4  =           T²

Square root each side:           2  =          T

When an object is dropped in Earth gravity,
it takes  2  seconds to fall the first 19.6 meters.

8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the angle of reflection
    14·2 answers
  • What 3 things can an object with unbalanced forces do?
    11·1 answer
  • Which waves move by replacing one particle with another
    11·2 answers
  • A stone is dropped at t = 0. A second stone, with 6 times the mass of the first, is dropped from the same point at t = 160 ms. (
    10·1 answer
  • We consider a projectile motion against a linear drag force D = −b∗v, where v is the velocity
    5·1 answer
  • A 20-kilogram box is sitting on an inclined plane with a 30-degree slope. If the box is at rest, what is the force
    14·1 answer
  • A dog chases a skateboarder travelling at 10.4\,\dfrac{\text{m}}{\text{s}}10.4 sm ​ 10, point, 4, start fraction, start text, m,
    12·1 answer
  • What is the effect of divorce on females?​
    8·2 answers
  • b) With the aid of diagrams, briefly describe an experiment to determine the density of an irregular shaped object (eg. stone).​
    10·1 answer
  • falling parachutist you bail out of the helicopter of example 3 and pull the ripcord of your parachute. now in eq. (3), so your
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!