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Dvinal [7]
2 years ago
7

A man inside an insulated metallic cage does not receive shock when the cage is highly charge .explain.

Physics
1 answer:
Luba_88 [7]2 years ago
5 0

A man inside an insulated metallic cage does not receive shock when the cage is highly charged because the whole charge reside on outer surface of the cage.

If the cage was a non-conductive cage, then the current cannot pass through the cage so it cannot affect the person in the cage.

For example- If you are seated in a car (metal body) and the car is hit with lightning, it is very unlikely that the person in the car would be hit with the lightning.

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Can someone help me?​
Leviafan [203]

Car X traveled 3d distance in t time.  Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t,  the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.

In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.

V_x .t' = 3d\\ \frac{3d}{t} .t' = 3d\\ t'=t

Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.

V_y.t = \frac{2d}{t} .t = 2d

We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.

4 0
3 years ago
A car weighs 1323 N. what is its mass?
Shalnov [3]
If the car is on the moon, its mass is about 817 kg.

If it's on the Earth, its mass is about 135 kg.
6 0
3 years ago
Read 2 more answers
An airplane traveling 919 m above the ocean at 505 m/s is to drop a case of twinkies to the victims below. How much time before
Elena L [17]

Answer:

a. 13.7 s b. 6913.5 m

Explanation:

a. How much time before being directly overhead should the box be dropped?

Since the box falls under gravity we use the equation

y = ut - 1/2gt² where y = height of plane above ocean = 919 m, u = initial vertical velocity of airplane = 0 m/s, g = acceleration due to gravity = -9.8 m/s² and t = time it takes the airplane to be directly overhead.

So,

y = ut - 1/2gt²

y = 0 × t - 1/2gt²

y = 0 - 1/2gt²

y = - 1/2gt²

t² = -2y/g

t = √(-2y/g)

So, t = √(-2 × 919 m/-9.8 m/s²)

t = √(-1838 m/-9.8 m/s²)

t = √(187.551 m²/s²)

t = 13.69 s

t ≅ 13.7 s

So, the box should be dropped 13.69 s before being directly overhead.

b. What is the horizontal distance between the plane and the victims when the box is dropped?

The horizontal distance x between plane and victims, x = speed of plane × time it takes for box to drop = 505 m/s × 13.69 s = 6913.45 m ≅ 6913.5 m

6 0
3 years ago
Science in the study of the natural world through. And.
Lyrx [107]
You need to finish the question
6 0
3 years ago
Considere que helicóptero para na altitude a que voava para largar uma caixa de 90 kg para o solo.
Firdavs [7]

Answer:

El peso es de 882 newton.

Explicación:

El helicóptero se detiene a la altura en la que volaba para dejar caer una caja de 90 kg al suelo, el peso de la caja llega hasta los 882 Newton porque el peso es una fuerza dirigida hacia el centro de la tierra y depende de la gravedad. La fórmula del peso es multiplicar la masa por la gravedad, de modo que cuando se multiplican 90 kg de masa por 9,8 metros / seg2, obtenemos el peso del objeto que es 882 newton.

7 0
3 years ago
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