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Dvinal [7]
3 years ago
7

A man inside an insulated metallic cage does not receive shock when the cage is highly charge .explain.

Physics
1 answer:
Luba_88 [7]3 years ago
5 0

A man inside an insulated metallic cage does not receive shock when the cage is highly charged because the whole charge reside on outer surface of the cage.

If the cage was a non-conductive cage, then the current cannot pass through the cage so it cannot affect the person in the cage.

For example- If you are seated in a car (metal body) and the car is hit with lightning, it is very unlikely that the person in the car would be hit with the lightning.

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You need to remove a broken light bulb from a lamp. without a pair of gloves, you are likely to cut yourself on the jagged glass
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3 years ago
Two engines create SIL values of 75 dB and 85 dB respectively. What dB reading would you expect when both are run simultaneously
stepladder [879]

Answer:

Explanation:

In a quiet forest, you can sometimes hear a single leaf fall to the ground. ... greater its pressure amplitude, the more the air is compressed in the sound it creates. ... Graphs of the gauge pressures in two sound waves of different intensities. ... The sound intensity level β in decibels of a sound having an intensity I in watts per .

4 0
3 years ago
A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of
balandron [24]

Answer:

The skater covers a distance of <u>15 m</u> before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

f=\mu N

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, N=mg

∴ f=\mu mg=0.490\times 90\times 9.8=432.18\ N

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

W=-fd=-432.18d

Now, change in kinetic energy is given as:

\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J

Therefore, from work-energy theorem,

W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m

Hence, the skater covers a distance of 15 m before stopping.

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