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Dvinal [7]
3 years ago
7

A man inside an insulated metallic cage does not receive shock when the cage is highly charge .explain.

Physics
1 answer:
Luba_88 [7]3 years ago
5 0

A man inside an insulated metallic cage does not receive shock when the cage is highly charged because the whole charge reside on outer surface of the cage.

If the cage was a non-conductive cage, then the current cannot pass through the cage so it cannot affect the person in the cage.

For example- If you are seated in a car (metal body) and the car is hit with lightning, it is very unlikely that the person in the car would be hit with the lightning.

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Which answer is a scientifically accurate description of velocity?
Tcecarenko [31]

The boat traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

Explanation:

A boat traveling from the dock northward to a 200m mark in the bay in less than 5minutes giving the passengers several more hours to fish is a typical and best example of velocity description.

Velocity is the displacement of a body divided by the time taken.

 Velocity = \frac{displacement}{time}

Displacement is the distance covered in a specific direction. Time is duration of the travel.

Velocity is a vector quantity that has both magnitude and direction. This implies that the value of velocity is recorded with a directional attribute.

We can say velocity is the speed of a body in a given direction

Only the last option gives the displacement of the body and the duration it traveled.

Learn more:

Velocity brainly.com/question/10883914

#learnwithBrainly

5 0
3 years ago
A 30 kg child sitting 5.0 m from the center of a merry-go-round has a constant speed of 5.0 m/s. while she remains seated in the
expeople1 [14]

Let us say that v is the tangential velocity of the object, a to be the centripetal (which acts towards the center of the circle) acceleration and F as the centripetal force, r to be the radius of the circle and m is mass of the child. <span>

a = v^2 / r 

F = ma = mv^2/r 

Applying the given values to the equation: 

F=30*(5^2/5) => 30*(25/5) => 30*5 => 150 Newtons</span>

Now work is Force times distance, the distance is simply the circumference of the circle.

d = C = 2 * pi * r = 2 * pi * 5 = 10π m

 

W = F * d = 150 N * 10π m

<span>W = 1500π J = 4712.39 J</span>

8 0
3 years ago
The manometer shown in fig. 2 contains water and kerosene. with both tubes open to the atmosphere, the free-surface elevations d
ozzi
The solution for this problem is: In the figure, you now know that total length of the kerosene column
So at x – xPatm + Pkg(H0 th) = Pa + Pwgh
Now H0 + h = 20 + 91.1 mm = 111.1 mm
Therefore = Pkg 0.1111 – P2g= h = 56 x 0.111 – 98 / 1000 x 9.81= 0.081 m or 81 mn
Therefore H0 = 111.1 - 81= 30.1 mm
6 0
3 years ago
At what speed, as a fraction of c, does a moving clock tick at four fifth the rate of an identical clock at rest?
ololo11 [35]

Answer:

The seed as a fraction of the speed of light is \frac{3}{5}c

Solution:

As per the question:

Suppose, t_{i} be the rate of an identical clock between two time intervals.

For a moving clock, moving with velocity 'v', at the clock tick of four-fifth:

t = \frac{5}{4}t_{i}

Now,

Using the relation of time dilation, from Einstein's relation:

t = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}

\frac{5}{4}t_{i} = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}

Squaring both sides:

(\frac{5}{4})^{2} = (\frac{1}{\sqrt{1 - \frac{v^{2}}{c^{2}}}})^{2}

\frac{25}{16} = \frac{1}{{1 - \frac{v^{2}}{c^{2}}}}

1 - \frac{16}{25} = \frac{v^{2}}{c^{2}}

\frac{v}{c} = \sqrt{\frac{9}{25}}

\frac{v}{c} = \frac{3}{5}

v = \frac{3}{5}c

6 0
3 years ago
Light from a 560 nm monochromatic source is incident upon the surface of fused quartz (n = 1.56) at an angle of 60°. What is the
MaRussiya [10]

Answer:

The angle of reflection is "60°".

Explanation:

The given values are:

Light from monochromatic source,

= 560 nm

Angle of incidence,

= 60°

Surface of fused quartz (n),

= 1.56

Whenever a light ray was indeed occurring at a flat surface, it should be the law or concept of reflection which contains this same rays of light, the reflected ray as well as the "normal" ray at either the mirror surface.

According to the above law,

⇒  Angle \ of \ incidence=Angle \ of \ reflection

then,

⇒  Angle \ of \ reflection=60^{\circ}

3 0
3 years ago
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