Two objects separated by a distance r are each carrying a charge q The magnitude of the force exerted on the second object by th
e first is F If the first object is removed and replaced with an identical object that carries a charge 4q what is the magnitude of the electric force on the second object
Explanation: Columbs law states that The force between the two point charges is directly proportional to the product of charges and inversely proportional to the square of distance between them
Force between the two charges is given by
F=K*q1*q2/r^2
if one charge become 4 times, new force is,
F=4(K*q1*q2)/r^2
F=4F
Where q1 and q2 are the point charges
r is the distance between the two charges
K is a constant of proportion called electrostatic force
okay this question seems easy. now if the 1.5 is vertically upwards so is that 2 is horizontally downwards hence as u say its 90 degrees thn it forms a right angled triangle.
1. neutral particles (neutrons) are in the nucleus 2. nucleus is in the nucleus 3. electron cloud is in the electron cloud 4. positively charged particles (protons) are in the nucleus 5. negatively charged particles (electrons) are in the electron cloud
