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shusha [124]
3 years ago
9

Two objects separated by a distance r are each carrying a charge q The magnitude of the force exerted on the second object by th

e first is F If the first object is removed and replaced with an identical object that carries a charge 4q what is the magnitude of the electric force on the second object
Physics
1 answer:
Sindrei [870]3 years ago
4 0

Answer:F=4F

Explanation: Columbs law states that The force between the two point charges is directly proportional to the product of charges and inversely proportional to the square of distance between them

Force between the two charges is given by

F=K*q1*q2/r^2

if one charge become 4 times, new force is,

F=4(K*q1*q2)/r^2

F=4F

Where q1 and q2 are the point charges

r is the distance between the two charges

K is a constant of proportion called electrostatic force

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A parachutist falls 50.0 m without friction. When the parachute opens, he slows down at a rate of 61 m/s^2. If he reaches the gr
ira [324]

Answer:

55.66 m

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While falling by 50 m , initial velocity u = 0

final velocity = v , height h = 50 , acceleration g = 9.8

v² = u² + 2gh

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v = 31.3 m /s

After that deceleration comes into effect

In this case final velocity v = 17 m/s

initial velocity u = 31.3 m/s

acceleration a = - 61 m/s²

distance traveled h = ?

v² = u² + 2gh

(17)² = (31.3)² - 2x 61xh

h = 690.69 / 2 x 61

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3 0
3 years ago
Simple Circuit and Ohm's Law Check-for-Understanding
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Answer:

current, only

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Wittaler [7]

Answer:

<h2>602.08 N</h2>

Explanation:

The force supplied by the train can be found by using the formula

f =   \frac{w}{d}  \\

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From the question we have

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We have the final answer as

<h3>602.08 N</h3>

Hope this helps you

7 0
3 years ago
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