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zvonat [6]
3 years ago
6

A truck slows from a velocity of 25 m/s to a stop in 70 m. What was the truck’s acceleration

Physics
1 answer:
igomit [66]3 years ago
4 0

v^2-u^2=2 x a x d

25^2-0^2=2 x a x 70

625-0=140 x a

625=140a

a=625/140

a=4.46 m/s^2

im not very sure but i think this is how you do this

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Answer:

(a) 0.345 T

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As per the question:

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Hall emf, V'_{Hall} = 69\ mV = 0.069\ V

Now,

Drift velocity, v_{d} = \frac{V_{Hall}}{B}

v_{d} = \frac{0.02}{0.10} = 0.2\ m/s

Now, the expression for the electric field is given by:

E_{Hall} = Bv_{d}sin\theta                            (1)

And

E_{Hall} = V_{Hall}d

Thus eqn (1) becomes

V_{Hall}d = dBv_{d}sin\theta

where

d = distance

B = \frac{V_{Hall}}{v_{d}sin\theta}                      (2)

(a) When \theta = 90^{\circ}

B = \frac{0.069}{0.2\times sin90} = 0.345\ T

(b) When \theta = 60^{\circ}

B = \frac{0.069}{0.2\times sin60} = 0.398\ T

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3 years ago
The conventional system of signs that indicate relative durations of long and short sounds is called.
Rudiy27

Musical notation is the term used to describe the common system of signs used to denote the relative duration of long and short sounds.

<h3>What is a musical notation?</h3>

Music notation, often known as musical notation, is any technique used to graphically express audibly perceived music performed with instruments or sung by a human voice using written, printed, or other symbol-based representations. This includes notation for periods of silence like rests.

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2 years ago
Inside a television picture tube there is a build-up of electrons (charge of 1.602 × 10^–19 C) with an average spacing of 38.0 n
Brut [27]
The magnitude of electric field is produced by the electrons at a certain distance.

E = kQ/r²

where: 
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Q = charge
r = distance
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Q = </span><span>1.602 × 10^–19 C
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8 0
3 years ago
Read 2 more answers
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Answer:

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From the Newton's law of universal gravitation,

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Then,

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F_{23} = \frac{6.67*10^{-11}*465*60 }{(0.17)^{2} }

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∴ F_{net} =  = 6.44 x 10^{-5} - 2.25 x 10^{-5}

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(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.

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Which increases the work output of a machine?
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