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3 years ago

A truck slows from a velocity of 25 m/s to a stop in 70 m. What was the truck’s acceleration

Physics

1 answer:

igomit [66]3 years ago

4 0

v^2-u^2=2 x a x d

25^2-0^2=2 x a x 70

625-0=140 x a

625=140a

a=625/140

a=4.46 m/s^2

im not very sure but i think this is how you do this

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Likurg_2 [28]

Answer:

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Explanation:

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The charge on proton, $q=1.6\times 10^{-19}\ C$

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$F=qvB\ sin\theta$

$F=1.6\times 10^{-19}\ C\times 1.8\times 10^6\ m/s\times 0.49\ Tsin(53)$

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3 years ago

A rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. Calculate the normal force (in N) acting on an a

goldenfox [79]

According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is -6048 N

<h3>What does Newton's third law say ?</h3>

The law state that in every action, there will be equal and opposite reaction.

Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.

Let us first calculate the force involved in the acceleration of the rocket by using the formula

F = ma

Where mass m = 87.4 kg, acceleration a = 69.2 m/s2

Substitute the two parameters into the formula

F = 87.4 x 69.2

F = 6048.08 N

According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.

Therefore, the normal force acting on the astronaut is -6048 N approximately

Learn more about forces here: brainly.com/question/12970081

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