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kari74 [83]
2 years ago
15

Find the value of x in the triangle

Chemistry
1 answer:
myrzilka [38]2 years ago
6 0

Answer:

55.52°

Explanation:

Concept tested: Sine rule of triangles

We need to know the sine rule

  • According to sine rule, if the three sides of a triangle are a, b and c and the corresponding angles, A, B and C
  • Then, \frac{a}{SinA}=\frac{b}{SinB}=\frac{c}{SinC}

In this case;

  • If we take, a = 5.7 units and A = 70°, and

         b= 5 units, B = x°

  • Using the sine rule we can find the value of x

Therefore;

\frac{a}{SinA}=\frac{b}{SinB}

Then;

\frac{5.7}{Sin70}=\frac{5}{Sinx}

6.0658=\frac{5}{sinx}

Sinx=0.8243

Therefore, X = 55.52°

Therefore, the value of x in the triangle is 55.52°

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What will be the final temperature of the solution in a coffee cup calorimeter if a 50.00 mL sample of 0.250 M HCl(aq) is added
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Answer:

21.21°C will be the final temperature of the solution in a coffee cup calorimeter.

Explanation:

HCl+NaOH\rightarrow H_2O+NaCl

\Delta H = enthalpy change = -57.2 kJ/mol of NaOH

Moles of sodium hydroxide = n

Molarity of the NaOH = 0.250 M

Volume of NaOH solution = V = 50.00 mL = 0.050 L

n=Molarity\times V=0.250 M\times 0.050 L= 0.0125 mol

Moles of HCl = n'

Molarity of the HCl= 0.250 M

Volume of HCl solution = V' = 50.00 mL = 0.050 L

n'=Molarity\times V=0.250 M\times 0.050 L= 0.0125 mol

Since 1 mole of Hcl reacts with 1 mole of NaoH. Then 0.0125 mole of HCl will react with 0.0125 mole of NaOH.

The enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

q=\Delta H\times n=-57.2 kJ/mol \times 0.0125 mol= -0.715 kJ=-715 J

q = heat released on reaction= -715 J

now, we calculate the heat gained by the solution.:

Q= -q = -(-715 J) = 715 J

m = mass of the solution = ?

Volume of the solution formed by mixing, v = 50.00 ml + 50.00 mL = 100.00 mL

Density of the solution = density of water = d = 1 g/mL

mass=density\times volume=d\times v=1 g/ml \times 100.00 ml=100 g

m = 100 g

q = heat gained = ?

c = specific heat = 4.18 J/^oC

T_{f} = final temperature = ?

T_{i} = initial temperature = 19.50^oC

Q=mc\times (T_{f}-T_{i})

Now put all the given values in the above formula, we get:

715 J=100 g\times 4.18J/^oC\times (T_f-19.50)^oC

T_f=21.21 ^oC

21.21°C will be the final temperature of the solution in a coffee cup calorimeter.

5 0
3 years ago
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