Molar mass:
O2 = 31.99 g/mol
C8H18 = 144.22 g/mol
<span>2 C8H18(g) + 25 O2(g) = 16 CO2(g) + 18 H2O(g)
2 x 144.22 g --------------- 25 x 31.99 g
10.0 g ----------------------?? ( mass of O2)
10.0 x 25 x 31.99 / 2 x 144.22 =
7997.5 / 288.44 => 27.72 g of O2
hope this helps!
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The ion in the cathode that gains electrons
Cl2=3.17g/L
Ne=.901g/L
CO2=1.96g/l
therefore Cl2 is the densest gas under the given conditions.
Answer:
0.18 mol
Explanation:
Given data
- Mass of carbon tetrachloride (solvent): 750 g
- Molality of the solution: 0.24 m
- Moles of iodine (solute): ?
Step 1: Convert the mass of the solvent to kilograms
We will use the relationship 1 kg = 1,000 g.

Step 2: Calculate the moles of the solute
The molality is equal to the moles of solute divided by the kilograms of solvent. Then,

Answer:1.58733
Explanation: About one and one sixth ounces