What is the name of cells that have the ability to develop into different<br> kinds of cells?

What is the value of the equilibrium constant at 25 oC for the reaction between the pair: I2(s) and Br-(aq) Give your answer usi

insens350 [35]

Explanation:

Formula to calculate standard electrode potential is as follows.

$E^{o}_{cell} = E^{0}_{cathode} - E^{0}_{anode}$

= 0.535 - 1.065

= - 0.53 V

Also, it is known that relation between $E^{o}_{cell}$ and K is as follows.

$E^{o}_{cell} = \frac{RT}{nF} \times ln K$

ln K = $\frac{nFE^{0}_{cell}}{RT}$

Substituting the given values into the above formula as follows.

ln K = $\frac{nFE^{0}_{cell}}{RT}$

= $\frac{2 \times 96485 C mol^{-1} \times -0.53 V}{8.314 l atm/mol K \times 298 K} \times \frac{1 J}{1 V C}$

ln K = -41.28

K = $e^{-41.28}$

= $1 \times 10^{-18}$

Thus, we can conclude that the value of the equilibrium constant for the given reaction is $1 \times 10^{-18}$ .

5 0

3 years ago

Which atom would be expected to have a half-filled <br> 3d subshell?

lana66690 [7]

Answer:

Manganese: Mn

Explanation:

The elestron configuration would show this is 25 electrons

Atomic number : 25

this electron configuration ends in $3d^{5}$

half of the d subshell which is 10

6 0

3 years ago

how much heat will be absorbed by 25g of chloroform when its temperature started at 67.0C and after it was 112.0C

snow_tiger [21]

Hello friend ☺

ΔH = MCΔT

ΔH = to the amount of energy or change in energy (J)

mass of water

C = waters specific heat capacity

ΔT = change in temperature

and so ΔH = 25 × 4.18 × ( 112-67 ) J = 4702.5 J

Thanks ❤

8 0

3 years ago

Which of the following options correctly ranks solid iodine, liquid bromine, and chlorine gas in order of increasing intermolecu

tatuchka [14]

Answer:

solid iodine chlorine gas

7 0

3 years ago

Calculate the maximum numbers of moles and grams of H₂S that can form when 158 g of aluminum sulfide reacts with 131 g of water:

Phantasy [73]

What is Chemical Reaction?

A chemical reaction is the chemical transformation of one set of chemical components into another.

Main Content

Mass of aluminium sulfide is 158g

Mass of water is 131g

The chemical reaction: $Al_{2}S_{3} +H_{2}O _\to Al(OH)_{3} + H_{2}S$

First, balance the chemical equation

$Al_{2}S_{3} + 6H_{2}O \to 2Al(OH)_{3} + 3H_{2}S$

Aluminium sulfide has a molar mass of 150.16 g/mol and water has a molar mass of 18.02 g/mol. As a result, the moles of aluminum sulfide are computed as follows:

$n_{Al_{2}S_{3} } = \frac{Mass}{Molar mass}\\n_{Al_{2} S_{3} } = \frac{158g}{150.16g/mol} \\n_{Al_{2}S_{3} }=1.05 mol$

From the chemical reaction , the ratio of molar is 3mol $H_{2}S/1 mol Al_{2}S_{3}.$ So, the moles of hydrogen sulfide are:

$n_{H_{2} O} =\frac{131g}{18.02g/mol}$

= 7.26mol

From the chemical reaction, the molar ratio is 3 mol $H_{2}S/6$ mol $H_{2}O.$ So, the moles of hydrogen sulfide are:

Moles of $H_{2}S$ formed = 7.26 mol $H_{2}O \times \frac{3 mol H_{2}S }{6 mol H_{2} O} }$

Th liming reactant is $Al_{2}S_{3}$ beacuse the mass of $Al_{2}S_{3}$ forms less product than water. Therefore, the maximum number of moles of $H_{2}S$ is 3.15 mol. We know that molar mass of $H_{2}S$ is 34.10g/mol. So, the maximum mass of $H_{2}S$ formed is,

$m_{H_{2}S } = n_{H_{2}S } \times$ Molar mass of $H_{2}S$

= 3.15 mol $\times$ 34.10g/mol

= 107.4g

Now, multiplying the number of moles of $Al_{2}S_{3}$ by the molar ratio between $Al_2S_3$ and $H_2O$ which is 6mol $H_2O/1mol$ $Al_2S_3$ we get the number of moles of $H_2O$ reacted.