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motikmotik
4 years ago
7

Classify ethynes as acids

Chemistry
1 answer:
luda_lava [24]4 years ago
4 0
Oxidation of acids giverise acids like oxalic acid and acetic acid
 Chemical properties of alkynes<span><span>Alkynes contain a triple bond (). A triple bond has one and two bonds.</span>Some characteristic reactions of alkynes are,CombustionAlkynes burns in air or oxygen with smoky flame.Electrophilic addition reactionsCarbon-carbon triple bond, C=C, is a combination of one and two bonds. Alkynes give electrophilic addition reactions as they show reactivity due to the presence of bonds. This property is similar to alkenes but alkynes are less reactive than alkenes towards electrophilic addition reactions due to the compact CC electron cloud. Some typical electrophilic addition reactions given by alkynes are:Addition of hydrogenAn alkyne reacts with hydrogen in the presence of catalyst (Pt or Ni) at 250°C, first forming alkenes and finally alkane.For example, ethyne gives ethane in two steps.ethyne etheneethaneEthane is obtained in good yields if hydrogenation is done with a calculated amount of hydrogen in the presence of palladium or barium sulphate.Propyne gives,
Addition of halogensAlkynes react with halogens (Cl2<span> or Br</span>2) in the dark, forming dihaloalkenes first and finally tetrahaloalkanes. The reaction gets accelerated in the presence of light or halogen carriers.RCCHRCX=CHXRCX2CX2alkyne dihaloalkene tetrahaloalkaneFor example, ethyne (acetylene) with chlorine gives,ethyne dichloroethene tetrachloroethaneDilute bromine water with ethyne gives dibromo, while liquid bromine gives tetrabromo derivative.tetrabromoethane ethyne 1,2-dibromoethene(acetylene)propyne gives,The order of reactivity is Cl2<span> > Br</span>2<span> > I</span>2.Addition of halogen acidsAlkynes reacts with halogen acids according to the Markownikoff's rule i.e. the carbon atom carrying the least number of hydrogen atoms will have the negative part of the addendum attached to it.For example, ethyne (acetylene) with HBr gives,With diluted HCl at 65°C and in the presence of Hg2+<span> (mercuric ion) ethyne gives vinyl chloride.</span>vinyl chloridePropyne givespropyne 2-bromopropene 2,2-dibromopropaneThe rate of addition of halogen acids follows the order, HI > HBr > HCl
MechanismAddition of hypochlorous acidAlkynes react with hypochlorous acid according to the Markownikoff's rule.For example, ethyne with HOCl gives,dichloroethanalIn the presence of peroxides the addition of HBr takes place according to the anti-MarkowniKoff's rule.Addition of sulphuric acidAlkynes add up two molecules of sulphuric acid. For example, ethyne givesNucleophilic addition reactionsAlkynes also give the following nucleophilic addition reactions.Addition of waterIn the presence of sulphuric acid (42%) and 1 % mercuric sulphate at 60°C, alkynes add on one water molecule to give aldehydes or ketones. For example,alkyne ketoneEthyne gives ethanal and propyne gives acetone.ethyne (acetylene) ethanal (acetaldehyde)
Addition of HCNAlkynes add one molecule of HCN in the presence of Ba(CN)2. For example,Ethyne givesethyne vinyl cyanide
Addition of ozoneOzone adds up across the triple bond to give ozonides. After hydrolysis, ozonides give diketones and carboxylic acids.Ethyne gives glyoxal and formic acid,glyoxal formic acid
Substitution reactionsDue to their acidic nature, alkynes form metallic salts called alkynides e.g., sodium, silver and copper(ous) salts. Examples are,Ethyne (acetylene) has two acidic hydrogen atoms, hence it finally gives dimetal salts.Acidic hydrogen in 1-alkynesHydrogen atoms in ethyne and 1-alkynes, linked to the carbon atom having a triple bond on it, are acidic in nature. For example, ethyne (acetylene) is a weak acid: weaker than water but stronger than ammonia. </span>
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How do you determine if and ion has a<br> noble-gasconfiguration?
Soloha48 [4]

Explanation:

Noble gas configuration is defined as the configuration which contains completely filled orbitals.

For example, oxygen atom when gain two electrons then it forms oxygen ion (O^{2-}).

Atomic number of oxygen atom is 8 and so, its number of electrons will also be 8. But when it gain two electrons then it has total 10 electrons. Hence, electronic configuration of O^{2-} is as follows.

          1s^{2}2s^{2}2p^{6}

Since, there are completely filled orbitals in an O^{2-} ions. Therefore, it means this ion has a  noble-gas configuration.

Thus, we can conclude that any specie which shows completely filled orbitals will have noble-gas configuration.

3 0
4 years ago
A pool owner adds a compound containing chlorine to the pool to disinfect it. However, too much of the compound is added. As a r
MrMuchimi

Answer: He could add a base to the pool to neutralize the acid.

Explanation:

Chlorine is used to disinfect the pools as it produces hypochlorous acid in water. This hypochlorous acid is unstable and gives hydrochloric acid and nascent oxygen which is used to disinfect.

Cl_2+H_2O\rightarrow HOCl

HOCl\rightarrow HCl+O

The excess acid is neutralized by adding base which produces salt and water and thus decrease the acidity.

Acid+Base\rightarrow Salt+water

Adding more acid would increase the acidity further.

3 0
3 years ago
Read 2 more answers
Help me now, please!
Nikitich [7]

Answer:

1. SnO2 = 1; H2 = 2; Sn = 1; H2O = 2

2. I mole of SnO2 is required to react with 2 moles of H2 to produce 1 mole of Sn and 2 moles of H20.

The balanced equation represents 1 mole of SnO2

3. Total mass of reactants and products are each 154.71g respectively

Explanation:

1. According to the law of conservation of mass, the total mass of reactants in a chemical reaction is equal to the mass of products.

Therefore, a balanced chemical equation has equal number of moles of each atom on the reactants side and on the product side. The balanced chemical equation for the reaction above will be:

Sn02 + 2H2 + Energy -----> Sn + 2H2O

Sn has 1 mole of atoms on both sides

O has 2 moles of atoms on both sides

H has 4 miles of atoms on both sides.

2. According to the balanced chemical equation above,

1 mole of SnO2 reacts with 2 moles of H2 to produce 1 mole of An and 2 moles of H20.

This balanced equation represents 1 mole of SnO2.

3. The atomic masses of Sn, O and H are 118.71g, 16g and 1g respectively.

Therefore, the molar masses of the reactants and products are;

SnO2 = 118.71 + 16 * 2 = 150.72g

H2 = 2 *1 = 2g

H2O = 2 * 1 + 16 = 18g

Total mass of reactants = 150.71g + 2 * 2g = 154.72g

Total mass of products = 118.71 + 2 * 18g = 154.71g

3 0
3 years ago
How does changing the mass of an object affect the density and the object if the volume is kept constant
vivado [14]

Explanation:

mass of an object affect the density and object if the the volume is keep constant.

here we can explain by using the example.

if the mass of an object is 30kg. and volume is 2m3

then density pf given substance is become 15kg/m3

again,

if the mass of the is 40kg/m3 and volume is same

then density is become 20kg/m3 (formula=kg/m3)

here above density and below density is becime different by changing the mass of an object and affect the density and objecy although volume is kept constant or same

7 0
3 years ago
Read 2 more answers
Suppose 650 mL of hydrogen gas are produced through a displacement reaction involving solid iron and sulfuric acid, H2SO4, at ST
scoray [572]

Answer:

                      4.415 g of FeSO₄

Explanation:

                   The balance chemical equation for given single replacement reaction is as follow;

                                  Fe + H₂SO₄ → FeSO₄ + H₂

Data Given;

                  Volume =  650 mL  =  0.65 L

                  Density at STP =  0.08988 g/L

                  Mass = Density × Volume = 0.08988 g/L × 0.65 L = 0.0584 g

Step 1: <u>Calculate Moles of H₂ as;  </u>

                  Moles  =  Mass / M.Mass

                  Moles  =  0.0584 g / 2.01 g/mol

                  Moles  =  0.0290 mol of H₂

Step 2: <u>Find out moles of FeSO₄ as;</u>

According to balance chemical equation,

            1 mole of H₂ is produced along with  =  1 mole of FeSO₄

So,

   0.0290 moles of H₂ will be produced along with  =  X moles of FeSO₄

Solving for X,

                    X  =  0.0290 × 1 mol / 1 mol

                    X =  0.0290 moles of FeSO₄

Step 3: <u>Calculate mass of FeSO₄ as;</u>

                   Mass  =  Moles × M.Mass

                   Mass  =  0.0290 mol × 151.90 g/mol

                   Mass  =  4.415 g of FeSO₄

4 0
3 years ago
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