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german
3 years ago
10

Be sure to answer all parts. calculate δg o for the reaction between i2(s) and br−(aq). e o cell = −0.54 j/c enter your answer i

n scientific notation. δg o = × 10 j

Chemistry
1 answer:
denpristay [2]3 years ago
3 0

Answer:

See explaination

Explanation:

See attachment for the detailed step by step solution of the given problem.

The attached file have the solved problem.

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The minerals hematite (Fe₂O₃) and magnetite (Fe₃O₄) exist in equilibrium with atmospheric oxygen:4Fe₃O₄(s) + O₂(g) ⇄ 6Fe₂O₃(s) K
iren2701 [21]

Kc at 298K is Kc = 1 × 10^84.

Calculation:

The relation between Kp and Kc is

      Kp = KcRT

The value of Kp is known

We can calculate the value of Kc with this

R =  8.3145 J mol^−1 K^−1 .

T = 298K

      Kp = KcRT

      2.5×10⁸⁷ = Kc × 8.3145 × 298

      2.5×10⁸⁷ = Kc × 2477.572

      Kc = 1 × 10^84

To learn more click the given link

brainly.com/question/25651917

#SPJ4

3 0
2 years ago
A water bath in a physical chemistry lab is 1.85m long, 0.810m wide and 0.740m deep. If it is filled to within 2.57 in from the
jenyasd209 [6]

Answer:

The volume of water in water bath is 1,011 Liters.

Explanation:

Length of the water bath, L = 1.85 m

Width of the water bath, W= 0.810  m

Height of the water bath ,H= 0.740 m

Height of the water in water bath, h= 0.740 m - 2.57 inches

1 m = 39.37 inch

= 0.740 m - \frac{2.57}{39.37} m = 0.6747 m

Volume of the water in bath = L × W × h

=1.85 m\times 0.810 m\times 0.6747 m=1.011 m^3

1 m^3=1000 L

1.011 m^3=1.011\times 1000 L=1,011 L

The volume of water in water bath is 1,011 Liters.

6 0
4 years ago
Which of the following are descriptive of the neutral atom with the electron configuration of 1s22s22p3?
Wittaler [7]

- It is in its ground state.

- It is an atom of Nitrogen.

- It has 3 electrons in its highest energy sublevel.

6 0
3 years ago
Read 2 more answers
Sodium hydroxide is used extensively in acid-base titrations because it is a strong, inexpensive base. A sodium hydroxide soluti
NeX [460]

Answer: The molarity of the base solution is 0.22 M.

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HCl solution = 0.1994 M

V_1 = volume of HCl solution = 38.87 ml

M_2 = molarity of NaOH solution = ?

V_2 = volume of NaOH solution = Final reading - Initial reading = 36.18 - 1.16 = 35.02 ml

n_1 = valency of HCl = 1

n_2 = valency of NaOH = 1

1\times 0.1994\times 38.87=1\times M_2\times 35.02

M_2=0.22M

Therefore, the molarity of the base solution is 0.22 M.

8 0
4 years ago
Read 2 more answers
At 20°C, a 0.756 M aqueous solution of ammonium chloride has a density of 1.0107 g/mL. What is the mass % of ammonium chloride i
Molodets [167]

Answer:

\%m/m=4\%

Explanation:

Hello,

In this case, by knowing that the molarity is measured in molal units which are mole per liter of solution and the by-mass percentage demands us to compute the mass of the solution, we proceed by assuming 1 L of solution:

m_{solution}=1L*\frac{1000mL}{1L}*\frac{1.0107g}{1mL} =1010.7g

Then, for 1 L of solution, we have 0.756 moles of solute (ammonium chloride), so we compute the grams for those moles by using its molar mass of 53.491 g/mol as shown below:

m_{solute}=0.756mol*\frac{53.491g}{1mol}=40.4g

Finally, we compute the by-mass percentage as shown below:

\%m/m=\frac{m_{solute}}{m_{solution}} *100\%=\frac{40.4g}{1010.7g}*100 \%\\\\\%m/m=4\%

Best regards.

6 0
3 years ago
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