Answer: no. Moles= 1.382moles
Explanation:
No. Of moles = mass/molar mass
NB : molar mass Al2O3= (27×2)+(16×3)= 102
n= 141/102 = 1.382moles
Answer:
V = 364500 L, 476.748 yard³
Explanation:
Given that,
The dimensions of a room are 10 meters wide by 15 meters long and 8.0 ft high.
l = 10 m, b = 15 m, h = 8 ft = 2.43 m
The volume of the room is :
V = lbh
So,
V = 10×15×2.43
V = 364.5 m³
As 1 m³ = 1000 L
364.5 m³ = 364500 L
Also, 1 m³ = 1.30795 yard³
364.5 m³ = 476.748 yard³
Hence, this is the required solution.
Answer:
= 18.75 L
Explanation:
Using the combined gas law;
P1V1/T2=P2V2/T2
Where; P1 is the initial pressure, 0.25 atm
V1 is the initial volume 300.0 L
T1 is the initial temperature, 400 K
P2 is 2 atm and
T2 is 200 K
Therefore;
(0.25 × 300)/400 = 2V2/200
V2 = (75 ×200)/(400×2)
= 18.75 L
Answer:
C) CH4 (g) + O2 (g)→ CO2 (g) + H2O (g)
Explanation:
Methane burns in the presence of air to give carbondioxide and water.
Also, All Alkanes combust in the presence of Oxygen to give carbondioxide and water.