Kc at 298K is Kc = 1 × 10^84.
Calculation:
The relation between Kp and Kc is
Kp = KcRT
The value of Kp is known
We can calculate the value of Kc with this
R = 8.3145 J mol^−1 K^−1 .
T = 298K
Kp = KcRT
2.5×10⁸⁷ = Kc × 8.3145 × 298
2.5×10⁸⁷ = Kc × 2477.572
Kc = 1 × 10^84
To learn more click the given link
brainly.com/question/25651917
#SPJ4
Answer:
The volume of water in water bath is 1,011 Liters.
Explanation:
Length of the water bath, L = 1.85 m
Width of the water bath, W= 0.810 m
Height of the water bath ,H= 0.740 m
Height of the water in water bath, h= 0.740 m - 2.57 inches
1 m = 39.37 inch

Volume of the water in bath = L × W × h



The volume of water in water bath is 1,011 Liters.
- It is in its ground state.
- It is an atom of Nitrogen.
- It has 3 electrons in its highest energy sublevel.
Answer: The molarity of the base solution is 0.22 M.
Explanation:
According to the neutralization law,
where,
= molarity of
solution = 0.1994 M
= volume of
solution = 38.87 ml
= molarity of
solution = ?
= volume of
solution = Final reading - Initial reading = 36.18 - 1.16 = 35.02 ml
= valency of
= 1
= valency of
= 1
Therefore, the molarity of the base solution is 0.22 M.
Answer:

Explanation:
Hello,
In this case, by knowing that the molarity is measured in molal units which are mole per liter of solution and the by-mass percentage demands us to compute the mass of the solution, we proceed by assuming 1 L of solution:

Then, for 1 L of solution, we have 0.756 moles of solute (ammonium chloride), so we compute the grams for those moles by using its molar mass of 53.491 g/mol as shown below:

Finally, we compute the by-mass percentage as shown below:

Best regards.