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vodka [1.7K]
3 years ago
9

Which of the following polynomials has zeros at x = –4 and x = 7?

Mathematics
2 answers:
Irina18 [472]3 years ago
8 0

Answer: The correct option is 4.

Explanation:

It is given that the polynomial has two zeros at x=-4 and x=7.

If a polynomial has zeros at x=c then (x-c) is a factor of the polynomial.

Since the polynomial has two zeros at x=-4 and x=7, therefore the polynomial has factor (x+4) and (x-7).

P(x)=(x+4)(x-7)

P(x)=x(x-7)+4(x-7)

P(x)=x^2-7x+4x-28

P(x)=x^2-3x-28

This equation is represented by option 4, therefore the option 4 is correct and the equation P(x)=x^2-3x-28 has zeros at x = –4 and x = 7.

Keith_Richards [23]3 years ago
4 0
The last one
x^2-3X-28
Z Z Z Z Z
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What are the coordinates of each point after quadrilateral ABCD is reflected across the y-axis and then translated 2 units down?
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Step-by-step explanation:

Given

A = (1,1)        B =(2,3)

C = (4,3)        D = (5,1)

Required

The new coordinates after reflected across y-axis and shifted 2 units down

When a point is reflected across the y-axis, the rule is:

(x,y)=>(-x,y)

So:

A = (1,1) => A' = (-1,1)

B =(2,3) => B' = (-2,3)

C = (4,3) => C' = (-4,3)

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When a point is translated 2 units down, the rule is:

(x,y) => (x,y-2)

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A = (1,1) => A' = (-1,1) => A" =(-1,-1)

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D = (5,1) => D' = (-5,1) => D" =(-5,-1)

So, the new coordinates are:

A" =(-1,-1)    B" =(-2,1)

C" =(-4,1)    D" =(-5,-1)

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