Heat required = 173 kJ
<h3>Further explanation</h3>
Given
56.0 g of ice
Temperatur at 263 K(-10 C) to 400 K(127 C)
Required
Heat needed
Solution
1. raise the temperature(-10 C to 0 C)⇒c ice=2.09 J/g C

2. phase change (ice to water)⇒Heat of fusion water=334 J/g

3. raise the temperature(0 C to 100 C)⇒c water= 4.18 J/g C

4. phase change(water to vapor)⇒heat of vaporization water=2260 J/g

5. raise the temperature(100 C to 127 C)⇒c vapor=2.09 J/g C

Total heat :
1170.4+18704+23408+126560+3160.08=173,002.48 J=173 kJ
<h3>
Answer:</h3>
62.3 mol Ca
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.75 × 10²⁵ atoms Ca
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
62.2717 mol Ca ≈ 62.3 mol Ca
Answer:
The correct answer is option D.
Explanation:
Step 1: 
Step 2: 
Overall reaction can be determined by adding all the reactions of mechanism:

Reactants in an overall reaction = 
Products in an overall reaction = 
According to question , the role of oxygen gas is product.
Weast to east , east to west, nort to south, south to nort.
Answer:
There are often not more than one or two independent variables tested in an experiment.