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NeX [460]
3 years ago
12

Moles /Number of Particles Con

Chemistry
1 answer:
Olin [163]3 years ago
7 0

(2.03x10^22)/(6.02x10^23) = .033721 mol Li

I hope this helps, if not, i am sorry

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Calculate the equilibrium constant for the reaction between fe2+(aq) and zn(s) under standard conditions at 25∘c.
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Following reaction occurs in the given electrochemical system:
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E(0) = E(0) Fe2+/Fe - E(0) Zn2+/Zn
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now, we know that, ΔG(0) =-nFE(0) ............... (1)
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On equating and rearranging equation 1 and 2, we get
K = exp( \frac{nFE(0)}{RT} )= exp (\frac{2X96500X0.323}{8.314X298}) = 8.46 x 10^{10}

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