Moles /Number of Particles Con

Which of the following is a property of matter?

lana66690 [7]

Explanation:

Matter also exhibits physical properties. Physical properties are used to observe and describe matter. Physical properties can be observed or measured without changing the composition of matter. These are properties such as mass, weight, volume, and density.

5 0

3 years ago

A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.

solniwko [45]

The missing question is:

<em>What is the percent efficiency of the laser in converting electrical power to light?</em>

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

$Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J$

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

$E = \frac{h \times c }{\lambda }$

where,

h: Planck's constant

c: speed of light

$E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J$

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

$\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J$

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

$Ef = \frac{Eo}{Ei} \times 100\% = \frac{1.74J}{130.0J} \times 100\% = 1.34\%$

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

You can learn more about lasers here: brainly.com/question/4869798

8 0

3 years ago

read carefully and do this questions all part all questions if someone do this questions I will make you brainly and give you th

Alex787 [66]

Answer:

2a. Calcium chloride

2b.hydrochloride acid

2c. water molecules

2d.hydrochloric acid

2e.carbon dioxide

Explanation:

CaCO3+2HCl＝CaCl2+CO2+H2O

5 0

3 years ago

Question 19 Write a balanced half-reaction for the oxidation of gaseous nitrogen dioxide to nitrate ion in acidic aqueous soluti

Alexxx [7]

Answer:

This will be the balanced half reaction:

NO₂(g) + H₂O (l) → NO₃⁻(aq) + 1 e⁻ + 2H⁺ (aq)

Explanation:

In acidic medium, the redox balance has to be done as this way.

As it is an oxidation, we know that oxidation state has increased.

NO₂(g) → NO₃⁻(aq) + 1 e⁻

Nitrogen in NO₂ acts with +4; in the nitrate, N acts with +5

The nitrogen has released 1 electron.

As we are in acidic medium, we must complete with water, in the same side, as we have less oxygens and in the opposite side, with protons to balance the H. This will be the balanced half reaction:

NO₂(g) + H₂O (l) → NO₃⁻(aq) + 1 e⁻ + 2H⁺ (aq)

5 0

3 years ago

Hotosynthesis can be represented by 6CO2(g)+6H2O(l)⇌C6H12O6(s)+6O2(g) Which of the following will be false when the photosynthes

antoniya [11.8K]

Answer: Option (b) and (d) are correct.

Explanation:

An equilibrium reaction is defined as the reaction in which rate of forward reaction equals rate of backward reaction.

A photosynthesis reaction is the reaction in which plants in the presence of sunlight, water, and carbon dioxide make their own food.

The amount of carbon dioxide consumed will be equal to the rate of formation of oxygen into the atmosphere.

Hence, the statement rate of formation of $O_{2}$ is equal to the rate of formation of $CO_{2}$ is true.

Concentration of oxygen may remain constant but it will not decrease. Hence, the statement concentration of $O_{2}$ will begin decreasing, is false.

As both oxygen and carbon dioxide are present in an equilibrium reaction, So, their concentration will not change.

Hence, the statement concentrations of $CO_{2}$ and $O_{2}$ will not change, is true.

Concentration of carbon dioxide and oxygen will also depend on the limiting reagent. So, it is not necessary that the concentrations of $CO_{2}$ and $O_{2}$ will be equal.

Some amount of carbon dioxide might escape out into the air.

Hence, the statement concentrations of $CO_{2}$ and $O_{2}$ will be equal, is false.

3 0

4 years ago