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NeX [460]
3 years ago
12

Moles /Number of Particles Con

Chemistry
1 answer:
Olin [163]3 years ago
7 0

(2.03x10^22)/(6.02x10^23) = .033721 mol Li

I hope this helps, if not, i am sorry

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A mixture of nitrogen and hydrogen gases, at a total pressure of 663 mm Hg, contains 3.46 grams of nitrogen and 0.156 grams of h
STALIN [3.7K]

<u>Answer:</u> The partial pressure of nitrogen gas is 405.76 mmHg and that of hydrogen gas is 257.24 mmHg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

  • <u>For nitrogen gas:</u>

Given mass of nitrogen gas = 3.46 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in above equation, we get:

\text{Moles of nitrogen gas}=\frac{3.46g}{28g/mol}=0.123mol

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 0.156 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

\text{Moles of hydrogen gas}=\frac{0.156g}{2g/mol}=0.078mol

Mole fraction of a gas is calculated by using the formula:

\chi_{A}=\frac{n_{A}}{n_{A}+n_{B}}      ......(1)

  • <u>For nitrogen gas:</u>

Putting values in equation 1, we get:

\chi_{\text{nitrogen gas}}=\frac{0.123}{0.123+0.078}=0.612

  • <u>For hydrogen gas:</u>

Putting values in equation 1, we get:

\chi_{\text{hydrogen gas}}=\frac{0.078}{0.123+0.078}=0.388

The partial pressure of a gas is given by Raoult's law, which is:

p_A=p_T\times \chi_A     ......(2)

where,

p_A = partial pressure of substance A

p_T = total pressure  = 663 mmHg

\chi_A = mole fraction of substance A

  • <u>For nitrogen gas:</u>

p_{\text{Nitrogen gas}}=663mmHg\times 0.612\\\\p_{\text{Nitrogen gas}}=405.76mmHg

  • <u>For hydrogen gas:</u>

p_{\text{Hydrogen gas}}=663mmHg\times 0.388\\\\p_{\text{Hydrogen gas}}=257.24mmHg

Hence, the partial pressure of nitrogen gas is 405.76 mmHg and that of hydrogen gas is 257.24 mmHg

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For the answer to the question above asking, e<span>ach row in the periodic table corresponds to one energy level in an atom.

The answer is true.

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