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g100num [7]
4 years ago
8

Which of the following represents the balanced reduction half-reaction from the redox reaction? (2 points)

Chemistry
1 answer:
-Dominant- [34]4 years ago
5 0

In general oxidation is defined as gain of oxygen or loss of electron or hydrogen by an atom. Reduction is defined as gain of electron or hydrogen or loss of oxygen by an atom.

In a balanced redox reaction we have two half reactions

a) reduction half reaction : the oxidation number of element decreases

b) oxidation half reaction : the oxidation number of element increases

Pb(s) + Pd(NO_{3} )_{2}(aq)---> Pb(NO_{3} )_{2}(aq)+ Pd(s)

The element undergoing reduction is Pd.

the oxidation number of Pd decreases from +2 to 0

Thus the reduction half reaction will be

Pd^{+2} + 2e- --->Pd(s)

The Pd (II) ion will take two electrons and will give Pd (0)

Answer is Pd^{+2} + 2e- --->Pd(s)

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Answer:

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7 0
3 years ago
A gas exerts a pressure of 1.8 atm at a temperature of 60 degrees celsius. What is the new temperature when the pressure of the
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The answer for the following problem is mentioned below.

  • <u><em>Therefore the final temperature of the gas is 740 K</em></u>

Explanation:

Given:

Initial pressure of the gas (P_{1}) = 1.8 atm

Final pressure of the gas (P_{2})  = 4 atm

Initial temperature of the gas (T_{1}) = 60°C = 60 + 273 = 333 K

To solve:

Final temperature of the gas (T_{2})

We know;

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        \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1}  = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of a gas

        \frac{1.8}{4} = \frac{333}{T_{2} }

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<u><em>Therefore the final temperature of the gas is 740 K</em></u>

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