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2 years ago

6x+3=38-x help please

Mathematics

1 answer:

Schach [20]2 years ago

4 0

Answer:

$x=5$

Step-by-step explanation:

$6x+3=38-x$

Subtract 3 from both sides:

$6x+3-3=38-x-3$

$6x=-x+35$

Add x to both sides:

$6x+x=-x+35+x$

$7x=35$

Divide 7 on both sides:

$\frac{7x}{7}=\frac{35}{7}$

$x=5$

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pychu [463]

Answer:

Step-by-step explanation:

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3 years ago

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A banner is in the shape of a right triangle. the area is 63 inches. The height of the banner is 4 in less than twice the width

Blizzard [7]

Area=1/2 times base times height
note:bh=base times height

a=1/2bh
b=width

h=-4+2w
h=2w-4
subsitute
a=1/2w(2w-4)
a=1/2(2s^2-4w)
a=w^2-2w
a=63
63=w^2-2w
subtract 63 from both sdies
0=w^2-2w-63
factor
find what 2 numbers multiply to get -63 and add to get -2
the numbers are -9 and 7
so
0=(w-9)(w+7)
if xy=0 then x and/or y=0

so
w-9=0
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solve each
w-9=0
add 9 to both sdies
w=9

w+7=0
subtract 7 from both sides
w=-7
width cannot be negative so this can be discarded

width=9

subsitute
l=2w-4
l=2(9)-4
l=18-4
l=14

legnth=14 in
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3 years ago

According to the fundamental theorem of algebra which polynomial function has exactly 8 roots? A.F(x)=(3x^2-4x-5)(2x^6-5) B.f(x)

choli [55]

I think it’s a because I added from the therum

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3 years ago

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qaws [65]

36 cm^2

Step-by-step explanation:

Small window

Length: 2cm

Width: 2cm

Area: 4 cm^2

Big window

Length: 4cm

Width: 3cm

Area: 12 cm^2

Total area of the windows:

(Area of 4 small windows + area of 1 big window)

(4 cm^2 x 4 + 12cm^2)

= 28 cm^2

Above window (approx.)

Rectangle

Length: 3cm

Width: 2cm

Area: 6 cm^2

Triangle

Base: 1cm

Height: 1cm

Area: 2 x 0.5 cm^2 = 1 cm^2

Square (between the triangles)

Length: 1cm

Width: 1cm

Area: 1 cm^2

= 8 cm^2

TOTAL AREA OF ALL WINDOWS

= AREA OF 4 WINDOWS + AREA OF BIG WINDOW + AREA OF ABOVE WINDOW

= 16 cm^2 + 12 cm^2 + 8 cm^2

I hope I made the explanations clear enough to make it easier for you to understand!

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1 year ago

Find the coordinates of the image of a triangle with vertices A(0, – 3), B(3, 0), and

lora16 [44]

Answer:

A'(-3,0), B'(0,-3) and C'(4,7)

Step-by-step explanation:

We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).

We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.

90° clockwise about the origin

Rule: $(x,y)\rightarrow (y,-x)$

Using the rule

The coordinates of A'

$A(0,-3)\rightarrow A'(-3,0)$

The coordinates of B'

$B(3,0)\rightarrow B'(0,-3)$

The coordinates of C'

$C(-7,4)\rightarrow C'(4,7)$

Hence, the vertices of image of triangle is given by

A'(-3,0), B'(0,-3) and C'(4,7)

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2 years ago