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Tresset [83]
3 years ago
8

Please please, please

Mathematics
2 answers:
Debora [2.8K]3 years ago
4 0

Answer:

graph Y seems to be the answer

Masja [62]3 years ago
3 0

The production of health drink cans at a warehouse can be represented by the equation below, where x represents the hours of production, and y the total supply of items in the warehouse, in hundreds.

Which of the following graphs represents this situation?

the equation is y= 3/5x+2

I drew the graph.

3/5 is the slope, and 2 is the y-intercept. So you start at (0,2), and go up 3 units, then right 5.

---

hope it helps

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Please answer this as soon as possible!! Please and thank you!
salantis [7]

Step-by-step explanation:

Find w

V = lwh

V ÷ lh = w

V/lh = w

w = V/lh

Option → C

3 0
2 years ago
How can i get the answer to this
kicyunya [14]
I believe it would be 20/15
6 0
3 years ago
Read 2 more answers
Maria is making a stained glass window in the form of a kite. the width of the window must be 15 in., and she only has enough st
NeTakaya
Kite Area = (Diagonal 1 * Diagonal 2) / 2
Diagonal 2 = 2 * Kite Area / Diagonal 1
Diagonal 2 =2 * 60 / 15
Diagonal 2 = 120 / 15
Height = 8 inches


4 0
3 years ago
Dont really understand
Llana [10]
Area is base times height, so take the 12 and 16 and multiply them, you will get 192 which is your answer
3 0
3 years ago
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In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day
nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

P(A \cap B) = 0.42*0.25 = 0.105

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

P(B|A) = \frac{0.105}{0.33} = 0.3182

31.82% probability that this day would be a winter day

6 0
3 years ago
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