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Sedaia [141]
3 years ago
9

3. In triangle ABC, m<BAC = 4x + 10, m<ABC = 5x + 18, and m<BCA = 3x - 16. (a) Find the value of x. (b) Find th

e measure of <3.

Mathematics
1 answer:
belka [17]3 years ago
7 0

(a) Find the value of x.

Sum of interior in a triangle = 180

So m<BAC  + m<ABC + m<BCA = 180

4x + 10 + 5x + 18 + 3x - 16 = 180

12x + 12 = 180

12x = 168

  x = 14


(b) Find the measure of <3.

<3 + <BCA = 180

<BCA = 3x - 16 = 3(14) - 16 = 26°

So

<3 = 180 - <BCA

<3 = 180 - 26

<3 = 154°

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Answer:  30 m ; (or, write as: "30 meters") .
______________________________________________
Explanation:
____________________

Area of a trapezoid, "A" = (1/2) ( b₁ + b₂) h ;
______________________________________________
or, write as:  A = ( b₁ + b₂) h  / 2 ;
___________________________________
in which:  A = area;
              b₁ = length of "base 1" (choose either one of the 2 (two bases);
              b₂ = length of "base 2" (use the base that is remaining);
              h = height of trapezoid;
____________________________________________
From the information given: 
___________________________
A = 100 m² ; 
h = 5 m
b₁ = 10 m
b₂ =  x 
___________________________
Find "x", which is:  "b₂" ;
__________________________
      A = ( b₁ + b₂) h  / 2  ;
_____________________________
Plug in our known values; and plug in "x" for "b₂" ; and solve for "x" ;
_________________________________________________________
  100 m² = [(10m + x) (5m)] / 2  ; Solve for "x" ;
_________________________________________________________
          (10m + x) (5m) = (2)* (100m²) ;
_________________________________________________________
             (5m) (10m + x) = 200 m² ;
___________________________________________
Note:  The distributive property of multiplication:
____________________________________________
    a(b+c) = ab + ac ;
 
    a(b−c) = ab <span>− ac ;
</span>____________________________________________

  We have:  (5m) (10m + x) = 200 m²  ;
____________________________________________
So:    (5m) (10m + x) =  (5m*10m) + (5m * x) ;
                           
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_______________________________________________
     →  50m² + (5m)x = 200m²  ; 
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Divide the ENTIRE equation by "5m" ;
_______________________________________________
     → { 50m² + (5m)x } / 5m = (200m² / 5m) ;
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     →  10m + x   = 40m ; 
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Now, subtract "10m" from EACH side of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
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     →  10m + x  − 10m  =  40m − 10m ;

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Answer:  30 m ; (or, write as: "30 meters") .
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