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3 years ago

If M = 5x2 + 7x - 4 and N = -3x2 - 4x + 5, then M - N equals

Mathematics

1 answer:

Alinara [238K]3 years ago

4 0

Answer

8x^2+11x-9

Step-by-step explanation:

That is the answer :))

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Saritza will find the area of the rectangle by tiling it with unit squares. The sides: 5/6 and 2/3. The question: Which is the a

AveGali [126]

A rectangle is a 2-dimensional shape with equal opposite sides. The appropriate side length for the unit square to tile Saritza’s rectangle to find the area will be 1/9 yard

<h3>How to find the area of a rectangle</h3>

A rectangle is a 2-dimensional shape with equal opposite sides.

Area of a rectangle = Length * width

Given the following parameters:

length = 5/6 yard

width = 2/3

Find the area

Area = 5/6 * 2/3
Area = 5/9 square units

The appropriate side length for the unit square to tile Saritza’s rectangle to find the area will be 1/9 yard

Learn more on area of rectangle here: brainly.com/question/2607596

3 0

2 years ago

What is not equivalent to 36/72

STALIN [3.7K]

Any fraction that does not equal 1/2.

6 0

3 years ago

Find a value for y for which the expression (1-y)(3-y)(6-y) has each given value

erik [133]

$\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=-70$

$\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=-70$

$\\ \tt\Rrightarrow y(2)(4)(7)=70$

$\\ \tt\Rrightarrow y(56)=70$

$\\ \tt\Rrightarrow y=\dfrac{70}{56}$

$\\ \tt\Rrightarrow y=\dfrac{5}{4}$

$\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=120$

$\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=120$

$\\ \tt\Rrightarrow -y(2)(4)(7)=120$

$\\ \tt\Rrightarrow 56y=-120$

$\\ \tt\Rrightarrow y=\dfrac{-120}{56}$

$\\ \tt\Rrightarrow y=\dfrac{-15}{7}$

7 0

2 years ago

Read 2 more answers

Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and

zzz [600]

Answer:

$\bold{sin(38^\circ)=cos(52^\circ)}$

Step-by-step explanation:

Given that $\triangle KJL$ is a right angled triangle.

$\angle JKL = 52^\circ\\\angle KLJ = 38^\circ$

and

$\angle KJL = 90^\circ$

Kindly refer to the attached image of $\triangle KJL$ in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given $\triangle KJL$ .

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

$sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

$sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}$ ....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

$cos\theta =\dfrac{Base}{Hypotenuse}$

$cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}$ ....... (2)

By (1) and (2):

sin(38°) $\neq$ cos(38°).

$cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}$ ...... (3)

Comparing equations (1) and (3):

we get the both are same.

$\therefore \bold{sin(38^\circ)=cos(52^\circ)}$

6 0

3 years ago

60 and 108 The GCF IS

CaHeK987 [17]

The greatest common divisor of these numbers is 12.

3 0

3 years ago

Read 2 more answers