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boyakko [2]
3 years ago
7

Write an equation in​ point-slope form of the line that passes through the given​ points, then write the equation in​ slope-inte

rcept for.
(-6,6) and (9,1)
What is the​ point-slope form of the equation of the​ line?
What is the​ slope-intercept form of the equation of the​ line?
Mathematics
1 answer:
frosja888 [35]3 years ago
8 0

As we go from (-6,6) to (9,1), x increases by 15 and y decreases by 5.  Thus, the slope of this line is m = rise / run = -5/15, or m = -1/3.

Point-slope form:  y-6 = (-1/3)(x+6), using data from (-6,6).  

Slope-intercept form:  starting with y = mx + b, substit. -6 for x, 6 for y and -1/3 for m:

6 = (-1/3)(-6) + b, or

6 = 2 + b.  Then b = 4, and the equation in slope-intercept form is

y = (-1/3)x + 4.

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If x-9 is a factor of x-5x-36 what is the other factor
dimaraw [331]
The other factor would be (x + 4). We can find this by using synthetic division. To do this, we must first find the divisor, which would be 9, if we let x - 9 equal to zero and solve for x. Then, for the dividend, we can use the coefficients and constant term values. 
<u>9</u>| 1  -5  -36
<u>         9  36</u>
     1  4  0
Therefore, the other expression (x + 9) would be (x + 4). Hope this helped!
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Step-by-step explanation

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Write an equation in point-slope form for the line that has a slope of 45 and contains the point (−5,−3).
olga55 [171]

Answer:

y+3=45(x+5)

Step-by-step explanation:

Hi there!

Point-Slope Form:

y-y1=m(x-x1)

Where

y1 stands for the y-coordinate of the point

m stands for the slope of the line

x1 stands for the x-coordinate of the point

In this case, the slope is 45, the y-coordinate of the given point is -3, and the x-coordinate of the point is -5.

Plug in the values and solve:

y-y1=m(x-x1)

y-(-3)=45(x-(-5)

y+3=45(x+5)

Hope it helps!

Enjoy your day!

Please feel free to ask if you have any doubts.

\bf{MysteriousSparkle}

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