Answer:
The rate of change is 0.75 gallons per minute
Step-by-step explanation:
The rate of change of the linear relation is represented by the slope of the line which represents this relation
The rule of the slope of a line is
m = Δy/Δx, where
- Δy is the vertical change
- Δx is the horizontal change
From the given graph
∵ The line passes through points (0, 0) and (4, 3)
∴ Δx = 4 - 0 = 4
∴ Δy = 3 - 0 = 3
→ Use the rule of the slope above to find the slope of the line
∴ m = 
= 0.75
∵ The x-axis represents the time in minutes
∵ The y-axis represents the amount in gallons
∵ m represents the rate of change
∴ The rate of change = 0.75 gallons per minute
Answer:
I think it will c because I have some eggs at home
Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ± 
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71
[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
Answer:
C
Step-by-step explanation:
The table shows that Sara earns 4 dollars per hour. The equation shows that Abbey earns 5 dollars per hour.
I hope that helps. If there are any questions left, just comment:)
Please mark me brainliest (it gets you 10 points back btw)
