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Allushta [10]
3 years ago
14

What are valence electrons ?

Chemistry
1 answer:
Arada [10]3 years ago
8 0

Answer:In chemistry, a valence electron is an outer shell electron that is associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.

Explanation: hope this helped

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Answer:

the answer is C

Explanation:

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Bisect tension can only be determined for a corner pole that has conductor spans of equal length on either side.
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A square mile = 27,878,400 square feet

A square mile also = 640 acres.

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For the reaction N2(g) + O2(g)2NO(g) H° = 181 kJ and S° = 24.9 J/K G° would be negative at temperatures (above, below) K. Enter
12345 [234]

ΔG deg will be negative above 7.27e+3 K.

<u>Explanation:</u>

  • The ΔG deg with the temperature can be found using the formula and the formula is given below
  • ΔG deg = ΔH deg - T ΔS deg
  • Given data, ΔH deg = 181kJ and ΔSdeg=24.9J/K
  • -T ΔS deg will be always negative and ΔG deg = ΔH deg  will  be  positive and ΔG deg will be negative at relatively high temperatures and positive at relatively low temperatures
  • solving the equation and substitute  ΔGdeg=0
  • ΔGdeg = ΔHdeg - T ΔSdeg
  • T= ΔHdeg/ΔSdeg
  • T=181 kJ / 2.49e-2 kJK-1
  • By simplification we get
  • T=7.27 × 10^3 K.
  • Therefore, Go will be negative above   7.27 × 10^3 K
  • Since ΔG deg = -RT lnK, when ΔGdeg < 0, K > 1 so the reaction will have K > 1 above 7.27 × 10^3 K.
  • ΔG deg will be negative above 7.27e+3 K.

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7 0
3 years ago
An unknown compound is processed using elemental analysis and found to contain 117.4g of platinum 28.91 carbon and 33.71g nitrog
dlinn [17]

Answer:

1 mole of platinum

Explanation:

To obtain the number of mole(s) of platinum present, we need to determine the empirical formula for the compound.

The empirical formula for the compound can be obtained as follow:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Divide by their molar mass

Pt = 117.4 / 195 = 0.602

C = 28.91 / 12 = 2.409

N = 33.71 / 14 = 2.408

Divide by the smallest

Pt = 0.602 / 0.602 = 1

C = 2.409 / 0.602 = 4

N = 2.408 / 0.602 = 4

The empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the formula of the compound (i.e Pt(CN)₄), we can see clearly that the compound contains 1 mole of platinum.

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