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patriot [66]
3 years ago
15

Find the volume of a cone with a height is two and the radius is three

Mathematics
1 answer:
irina [24]3 years ago
8 0
The volume of the cone is 18.85
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A game store recieved a shipment of puzzles.The puzzles are stacked in 6rows with 6 boxes in each row.Each box contains 6 puzzle
IRINA_888 [86]
I think it’s 216) because you do 6 times 6 then times that by 6
4 0
4 years ago
A box​ (with no​ top) will be made by cutting squares of equal size out of the corners of a 2626 inch by 4343 inch rectangular p
Troyanec [42]

If x represents the side length of the square cut from each corner, then the dimensions of the base of the box are 26-2x by 43-2x. The volume of the box is

... V = x(26-2x)(43-2x)

where x is restricted to the domain 0 ≤ x ≤ 13.

Plotting this equation using a graphing calculator shows the maximum volume to be 2644.7 in³.

_____

The analytical solution can be found by setting the derivative of V to zero.

... V = 4x³ - 138x² +1118x

... dV/dx = 0 = 12x² -276x +1118

This has solutions given by the quadratic formula, where a=12, b=-276, c=1118:

... x = (-b±√(b²-4ac))/(2a)

The plus sign will give a solution that is not in the allowed domain of x, so the only viable solution is the one where the radical is subtracted.

... x = (276 - √(76176--53664))/24 = (23/2) - √(469/12) ≈ 5.2483 . . . inches

Then the corresponding maximum volume is found from the equation for V.

... V ≈ (5.2483)(26 - 2·5.2483)(43 - 2·5.2483) ≈ 2644.6877 in³ . . . . as above

5 0
3 years ago
On the planet of Mercury, 4-year-olds average 3 hours a day unsupervised. Most of the unsupervised children live in rural areas,
erastova [34]

Answer:

a

The distribution of  X is normal

b

P(X  <  1.4) = 0.12654

c

P(X  >  3.5) = 0.36051

Step-by-step explanation:

From the question we are told that

   The population mean is  \mu =  3 \  hours

   The standard deviation is  \sigma  =  1.4 \ hours

Generally given from the question that the amount of time spent alone by the population size is normally distributed then then the distribution of X (i.e the amount of time spent by the sample size (the one Mercurian)) will be normally distributed

  Generally the probability that the child spend less than one hour in a day is mathematically represented as

        P(X  <  1.4) =  P(\frac{X - \mu}{\sigma} < \frac{1.4 - \mu}{\sigma}   )

Here \frac{X - \mu}{\sigma }  =  Z (The\ standardized\ value\ of\  X)

So

      P(X  <  1.4) =  P(Z < \frac{1.4 - 3.0}{1.4}   )

     P(X  <  1.4) =  P(Z < -1.1429  )

From the z-table the value of  

        P(Z < -1.1429  )=0.12654

So     P(X  <  1.4) = 0.12654

Generally the percentage of children that spends over 3.5 hours unsupervised is mathematically represented as

        P(X  >  3.5) =  P(\frac{X - \mu}{\sigma} > \frac{3.5 - \mu}{\sigma}   )

        P(X >  3.5) =  P(Z > \frac{3.5 - 3.0}{1.4}   )

        P(X >  3.5) =  P(Z > 0.3571  )

From the z-table the value of  

        P(Z >0.3571  )=0.36051

So     P(X  >  3.5) = 0.36051

5 0
3 years ago
I need help can you help with a-d?
never [62]

Answer:

manage to find for a

it's just a matter of counting the numbers and colours

5 0
3 years ago
Steven just got a new summer job painting fences in his neighborhood. He will be paid $7.25 an hour. His first customer paid him
aliya0001 [1]

Answer:

Part A: 7.25x = 36.25

Part B: 5 hours

Step-by-step explanation:

36.25/7.25 = 5

8 0
3 years ago
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