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nataly862011 [7]
3 years ago
6

When hydrogen is heated or subjected to an electric discharge, it emits light with specific visible wavelengths. A diffraction g

rating having a spacing between adjacent lines of 4926 nm is used in an experiment to study the visible spectrum of hydrogen. The hydrogen light is sent through the grating and the light emitted by the hydrogen at 656 nm is observed. At what angle does the fourth order bright fringe occur for this specific wavelenth of light occur?
Physics
1 answer:
BartSMP [9]3 years ago
3 0

To solve this problem we will apply the concepts related to the double slit-experiment. For which we will relate the distance between the Slits and the Diffraction Angle with the order of the bright fringe and the wavelength, this is mathematically given as,

d sin\theta = m\lambda

Here,

d = Distance between Slits

m = Order of the fringes

\lambda = Wavelength

\text{Spacing between adjacent lines} = d = 4926nm

\text{Wavelength of light} = \lambda = 656nm

Rearranging to find the angle,

sin\theta = \frac{m\lambda}{d}

\theta = sin^{-1}(\frac{m\lambda}{d})

\theta = sin^{-1}(\frac{(4)(656*10^{-9}m)}{4926*10^{-9}m})

\theta = 32.19\°

Therefore the angle that the fourth order bright fringe occur for this specific wavelenth of light occur is 32.19°

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B!!!

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Answer:

F= 134.92 N

Explanation:

Given that

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The radius ,R= 1.7 x 10⁶ m

The force exerted by moon is given as

F=G\dfrac{Mm}{R^2}

Now by putting the values in the above equation we get

F=6.67\times 10^{-11}\times \dfrac{79\times 7.4\times 10^{22}}{(1.7\times 10^6)^2}\ N\\F=134.92 N

Therefore the force will be 134.92 N.

F= 134.92 N

8 0
3 years ago
A mass of 8kg is suspended from a spring with a spring constant of 16N/m and then released, creating periodic motion. At what di
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The spring will come to rest 4.9 m below the natural length

Explanation:

The mass-spring system will come to rest when the restoring force on the spring (pulling upward) balances the weight of the mass (pulling downward). Mathematically, this can be written as

F_x = W\\kx = mg

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k is the spring constant

x is the elongation of the spring

m is the mass

g is the acceleration of gravity

In this problem, we have:

m = 8 kg is the mass

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k=16 N/m is the spring constant

Solving the equation for x,

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Therefore, the spring will come to rest 4.9 m below the natural length.

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A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift i
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Total work done = = 29811.60 J

Explanation:

Since the person is being moved upward, the person’s potential and kinetic energy are increasing.

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Increase in kinetic energy is given by the following equation;

∆ KE = ½ * m * (vf² – vi²)

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(b) He is then lifted at the constant speed of 3.40 m/s

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∆ PE = 9937.20 J

(c) He is then decelerated to zero speed.

Since his velocity decreased from 3.40 m/s to 0 m/s, his kinetic energy decreased.

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Sum of works = 10388.04 + 9937.20 + 9486.36 = 29811.60 J

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