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omeli [17]
3 years ago
11

The picture shows the inside of an eye.

Physics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

Hello, Your answer is <em>D) Lens and Corena</em>

Explanation:

<em>Because the lens goes direct to the light rays and it helps them to focus on light sensitive, and the corena act on a outermost when light strike the corena helps bends or "</em><em>Refracts</em><em>" into the income light onto the lens. The only problem it's not "Retina and optic nerve" because the Retina and optic nerve goes to connects the eyes to the brain. And it not B. because the and "Rods and Cone" are responsible for vision at the </em><u><em>"Low lights Levels".</em></u><em> Maybe it could be C. But the only problem is the "iris and the pupil" are at the ring shape that surrounds at the opening area. </em><em>So your best answer will be D </em><u><em>Lens and Corena. Have a Great day!</em></u>

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A ball is thrown straight up from the ground with speed v0. At the same instant, a second ball is dropped from rest from a heigh
dlinn [17]

Answer:

a) t = H/v0

b) H = -(v0)²/g

Explanation:

Hi there!

a)The position of the balls can be calculated using the following equation:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the ball at time t.

y0 = initial height.

v0 = initial velocity.

g = acceleration due to gravity.

t = time.

For the ball that is thrown upwards, the initial height is zero, then, the equation can be written as follows:

y = v0 · t + 1/2 · g · t²

The second ball is initially at a height H and the initial velocity is zero. The equation of height for the second ball will be:

y = H + 1/2 · g · t²

When the two balls collide, their height is the same. Then, equalizing both equations we can obtain the time at which they collide:

v0 · t + 1/2 · g · t² = H + 1/2 · g · t²

v0 · t = H

t = H/v0

b) When the first ball is at the highest point its velocity is zero. Using the equation of velocity we can find the time at which the ball is at that point. The equation of velocity is the following:

v = v0 + g · t

At the highest point v = 0.

0 = v0 + g · t

Solving for t:

-v0/g = t

The time at which the first ball is at the highest point is t = -v0/g

The time at which both balls collide was calculated above:

t = H/v0

Then, equalizing both times and solving for H:

H/v0 = -v0/g

H = -v0/g · v0

H = -(v0)²/g

3 0
3 years ago
Based on Kepler's work, which best describes the orbit If a planet around the Sun?
krek1111 [17]

Answer:

an ellipse with the Sun at one focus  or D

Explanation:

Answer for edgenuity

7 0
3 years ago
There is a force between two charges; if the distance between the two charges is doubled, by what factor does the force between
Luba_88 [7]
It will double it and yes it will change them.
4 0
3 years ago
Read 2 more answers
A spacecraft left Earth to collect soil samples from Mars. Which statement is true about the strength of Earth’s gravity on the
ryzh [129]

Answer:

: It Decreases.

As the spacecraft gets farther and farther from Earth, the gravitational  

forces between the spacecraft and the Earth decrease.

Explanation:

5 0
3 years ago
Question 4 - If Angelica starts out at 30m/s, and in 16 s speeds up to 84 m/s, what is her acceleration?
Triss [41]

Answer:

C. 3.375 m/s^2

Explanation:

The acceleration of an object can be found using the equation:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time it takes for the velocity to change from u to v

In this problem:

u = 30 m/s is the initial velocity of Angelica

v = 84 m/s is the final velocity

t is the time

Substituting into the equation, we find the acceleration:

a=\frac{84-30}{16}=3.375 m/s^2

4 0
3 years ago
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