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zavuch27 [327]
2 years ago
7

Cal ulate a moment of force o. 50 meter distance and 10 newton force​

Physics
1 answer:
lina2011 [118]2 years ago
8 0

Answer:

500N/M

Explanation:

given that

force=10N

distance=50M

moment=force*distance

=10×50=500j

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Answer:

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Explanation:

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Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm

Hence the focal length of the convex lens is 20cm

7 0
3 years ago
A 25 n object requires a 5.0 n to start moving over a horizontal surface. what is the coefficient of static friction?
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thus the coefficient of static friction will be 5 N÷ 25 N =  0.2
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3 years ago
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