Answer:
2.80 MJ
Explanation:
(a) We want to calculate the energy U of the battery, where its voltage is E = 13.0V and the supplied current is I = 60 A. We can neglect the internal resistance, so the terminal voltage equals the emf of the battery V = 13.0V. The quantity of delivered energy is given by the rate at which energy is delivered to it in a certain time t. We could obtain the rate at which energy is transferred by using equation , where the rate represents the power P = IV. Therefore, the energy produced is given by
U = P*t (P = IV)
U = I*V*t (1)
Now we can plug our values for I, V and t into equation (1) to get the energy produced in time t = 1 h = 3600 s
U = I*V*t = (60 A)(13 V)(3600s) = 2.80 MJ
Answer:
L= 12 light years
Explanation:
for length dilation we use the formula
now calculating Lo
Lo = 12.5×365×24×3600×3×10^8
= 1.183×10^17 m
now putting the values of v and Lo in the above equation we get
= 1.136×10^17 m
L= 
m
so L= 12 light years
Answer:
$4.2
Explanation:
Given data
Power= 700W
time= 10 hours
Cost per kilowatt hours is cents $0.20
Let us find the number of hours in a month
=24*30
=720 hours
Energ= power*time
Energy= 700/1000*30
Energy= 7*3
Enery= 21 kwh
1 kwh= 0.2
21kwh= x
cross multiply
x=21*0.2
x= $4.2
