All categories

3 years ago

The law of universal gravitation

Physics

1 answer:

Naddik [55]3 years ago

8 0

The law of universal gravitation applies everywhere
for everything that has mass.

You might be interested in

State one advantage and disadvantage of friction

yuradex [85]

Answer:

Advantage: Helps us to walk without slipping.
Helps machines work

Disadvantage:

We slip on a wet floor.
Causes the smoothness of tires and smoothness of shoes soul.

5 0

2 years ago

PLEWSE SOMEONE HELP ILL MARK BRAINLIST

Margaret [11]

Answer:

Explanation:

ffhjjxghjjcdddhhgfd

Brainliest pls ❤️

3 0

3 years ago

Read 2 more answers

A student is running to catch the campus shuttle bus, which is stopped at the bus stop. The student is runnign at a constant spe

Serggg [28]

Answer:

Part a)

$t = 16.8 s$

$d = 100.8 m$

Part b)

$v_f = 2.86 m/s$

Explanation:

Part a)

Constant speed by which the student will run is given as

$v = 5 m/s$

now after some time if student is going to overtake the position of bus

so here the final positions will be same

so we have

$x_{bus} = x_{student}$

$0 + \frac{1}{2}at^2 + d = v_{student} t$

$\frac{1}{2}(0.170)t^2 + 60 = 5 t$

$0.085 t^2 - 5t + 60 = 0$

so it is

$t = 16.8 s$

So student will run the total distance

$d = vt$

$d = (6)(16.8)$

$d = 100.8 m$

Part b)

Speed of bus when student reach the bus is given as

$v_f = v_i + at$

$v_f = 0 + (0.170)(16.8)$

$v_f = 2.86 m/s$

4 0

4 years ago

6. Willingness to take turns is one way we can express our attitudes in

NNADVOKAT [17]

The answer is A ..........

5 0

3 years ago

Marcia flew her ultralight plane to a nearby town against a head wind of 15 km/h in 2h 20 min. the return trip under the same wi

insens350 [35]

Let the distance between the towns be d and the speed of the air be s.

distance = speed * time

convert the minutes time into hours.

When flying into the wind, ground speed will be air speed MINUS wind speed, hence the against the wind trip is described by:

s−15

return trip is then :

s+15

Cross-multiplying both we get the two-variable system:

3d=7∗(s−15)5d=7∗(s+15)

3d=7s−1055d=7s+105

subtract first equation from second equation we get

2d=210d=105km

Substitute the value of d in the above equations for s.

5∗105=7s+1057s=420s=60km/hr

8 0

3 years ago

Read 2 more answers