Here is your answer
b) 
REASON :
We know that
Velocity= Frequency× Wavelength
So,
Frequency= Velocity/wavelength
Here,
V= 3× 10^8 m/s
Wavelength= 2×10^-3 m
Hence,
Frequency= 3×10^8/2×10^-3
= 3/2 × 10^11
= 1.5× 10^11 Hz
HOPE IT IS USEFUL
Answer:
the temperature would Increase and pressure would increase
Explanation:
This would occur because the temperature would move to the liquid through conduction and the pressure would increase because the heat would cause more and more pressure
Answer:
he electron is directly transferred to NADP+ to NADPH, but electron flow is used to generate a proton gradient for ATP synthesis. Electron is not directly transferred to ATP
NADP= Nicotin amide adenine dinucleotide phosphate
NADPH =Nicotinamide adenine dinucleotide phosphate is the reduced form of NADP
therefore electron is not directly transferred to ATP
Answer:
The final velocity of the object is, 
= 27 m/s
Explanation:
Given,
The acceleration of the object, a = 1000 m/s²
The initial displacement of the object, 
= 0 m
The final displacement of the object, 
= 0.75 m
The initial velocity of the object will be, 
= o m/s
The final velocity of the object, = ?
The average velocity of the object,
v = ( - )/ t
= 0.75 / t
The acceleration is given by the relation
a = v / t
1000 m/s² = 0.75 / t²
t² = 7.5 x 10⁻⁴
t = 0.027 s
Using the I equation of motion,
= u + at
Substituting the values
= 0 + 1000 x 0.027
= 27 m/s
Hence, the final velocity of the object is, = 27 m/s
Answer:
the intensity of the light after passing through the two polarizing filters is 4.11 units
Explanation:
Given the data in the question;
the intensity of an unpolarized light; I₀ = 25.0 units
when the unpolarized light passes through the first polarizer, its intensity reduces to half of its initial value;
⇒ I₁ = I₀/2 = 25/2 = 12.5 units
the angle between the transmission axes of two polarizers is;
∅ = 55° - 0° = 55°
The intensity of the light after passing through two polarizing filters will be;
I₂ = I₁cos²∅
we substitute
I₂ = 12.5 × cos²(55)
I₂ = 12.5 × 0.3289899
I₂ = 4.11 units
Therefore, the intensity of the light after passing through the two polarizing filters is 4.11 units
