A snail crawls 5 inches in 15 minutes. What is its speed in in./min?
1 answer:
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Answer:
Below
Explanation:
First draw the vectors that represent both electric fields.
E1 is the elictric field created by q1, E2 is the one created by q2.
● q1 is negative so E1 will point from P.
● q2 is positive so E2 will point out of P
(Picture below)
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The resulting electric field is equal to the sum of the two fields since both vectors are colinear.
Let E be the total field.
● E = E1 + E2
The formula of the electric field intensity is:
● E = K ×(q/d^2)
-K is Coulomb's constant
-d is the distance between the charge and the object ( here P)
-q is the charge
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● E1 = K × (q1/d1^2)
The distance between q1 and P is the qum of 0.15 m 0.25 m. (0.4 m)
Coulombs constant is 9×10^9 m^2/C^2
● E1 = 9×10^9 ×[-6.39 × 10^(-9)/ 0.4^2]
● E1 = -359.43 N/C
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● E2 = K ×(q2/d^2)
The distance between q2 and P is 0.25 m.
● E2 = 9×10^9×[3.22×10^(-9) /0.25^2]
● E2 = 463.68 N/C
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● E = E1 + E2
● E = -359.43+463.68
● E = 105.25 N/C
Answer:
The centripetal acceleration as a multiple of is
Explanation:
The centripetal acceleration is defined as:
(1)
Where v is the velocity and r is the radius
Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:
(2)
Where r is the radius and T is the period.
For this case the person is standing at a latitude . Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.
It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.
(3)
Where is the radius at the latitude of
and
is the radius at the equator (
).
can be isolated from equation 3:
(4)
Then, equation 2 can be used
Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.
⇒
Finally, equation 1 can be used:
Hence, the centripetal acceleration is
To given the centripetal acceleration as a multiple of it is gotten:
