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Vinil7 [7]
3 years ago
13

Convert 163°F to kelvins.

Chemistry
1 answer:
marysya [2.9K]3 years ago
4 0
Answer: 344.927778
Work: T(k)=(T(°F)+459.67)x5/9
T(K)=(60°F+459.67)x5/9=288.71 K
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Why does hydrochloric acid have a higher boiling point than diatomic fluorine?Why does hydrochloric acid have a higher boiling p
beks73 [17]

Hydrochloric acid is polar which means it has stronger bonds between it's molecules, unlike diatomic fluorine that is non-polar and has weaker bonds. That's why it has a higher boiling point.

8 0
4 years ago
Yall help, i missed like a week<br>some of them are wrong, I need all of 1 and 2​
Stolb23 [73]

Answer:

a. Azane

b. sulphur hexachloride

c.carbon tetrachloride

d. Carbon disulfide

e.Umbelliferone

f.Disilicon hexabromide

g. Dinitrogen trifluoride

h.

8 0
3 years ago
A sample of SO2 gas at 0.821 atm occupies 4.24 L at 35°C, Calculate the new volume of the gas if the pressure is increased to 1.
Marysya12 [62]
Use the P1V1/T1=P2V2/T2 formula
4 0
3 years ago
Determine the number of miles of H in each sample;
Inessa [10]

1) Answer is: there are 9.04 moles of the hydrogen in 4.52 mol of the water.

n(H₂O) = 4.52 mol; amount of the water molecules.

In one molecule of the water, there are two hydrogen atoms.

n(H₂O) : n(H) = 1 : 2.

n(H) = 2 · n(H₂O).

n(H) = 2 · 4.52 mol.

n(H) = 9.04 mol; amount of the hydrogen atoms.

2) Answer is: there are 25.29 moles of the hydrogen in 8.43 mol of the ammonia (NH₃).

n(NH₃) = 8.43 mol; amount of the ammonia molecules.

In one molecule of the ammonia, there are three hydrogen atoms.

n(NH₃) : n(H) = 1 : 3.

n(H) = 3 · n(NH₃).

n(H) = 3 · 8.43 mol.

n(H) = 25.29 mol; amount of the hydrogen atoms.

3) Answer is: there are 0.408 moles of the hydrogen in 0.102 mol of the hydrazine (N₂H₄).

n(N₂H₄) = 0.102 mol; amount of the hydrazine molecules.

In one molecule of the hydrazine, there are four hydrogen atoms.

n(N₂H₄) : n(H) = 1 : 4.

n(H) = 4 · n(N₂H₄).

n(H) = 4 · 0.102 mol.

n(H) = 0.408 mol; amount of the hydrogen atoms.

4) Answer is: there are 770 moles of the hydrogen in 35.0 moles of the decane (C₁₀H₂₂).

n(C₁₀H₂₂) = 35.0 mol; amount of the decane molecules.

In one molecule of the decane, there are twenty two hydrogen atoms.

n(C₁₀H₂₂) : n(H) = 1 : 22.

n(H) = 22 · n(C₁₀H₂₂).

n(H) = 22 · 35.0 mol.

n(H) = 770 mol; amount of the hydrogen atoms.

6 0
3 years ago
Use trigonometric identities to solve tan(2theta)+tan(theta)=0 exactly for 0
hoa [83]
Tan2(∅) ≡ 2tan(∅) / (1 - tan²∅)

Thus,
2tan(∅) / (1 - tan²(∅)) + tan(∅) = 0
2tan(∅) / (1 - tan²(∅)) = -tan(∅)
1 - tan²(∅) = -2
tan²(∅) = 3
∅ = tan⁻¹(√3)
∅ = 4nπ/3
4 0
4 years ago
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