All categories

3 years ago

In a titration how much 0.50 M HCl is needed to neutralize 1 liter of a 0.75 M solution of NaOH?

Chemistry

1 answer:

Ymorist [56]3 years ago

6 0

Answer:

1.5 L

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above, The mole ratio of the acid (nA) = 1

The mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question. This includes the following:

Molarity of acid (Ma) = 0.5M

Volume of acid (Va) =..?

Volume of base (Vb) = 1L

Molarity of base (Mb) = 0.75M

Step 3:

Determination of the volume of the acid needed for the reaction.

Using the formula:

MaVa/MbVb = nA/nB

The volume of the acid needed for the reaction can be obtained as follow:

0.5 x Va / 0.75 x 1 = 1

Cross multiply

0.5 x Va = 0.75 x 1

Divide both side by 0.5

Va = 0.75 /0.5

Va = 1.5 L

Therefore, the volume of the acid, HCl needed for the reaction is 1.5L

You might be interested in

Asap please help !!!!

Liula [17]

Answer: What do you need help with?

Explanation:

A biome is a collection of plants and animals that have common characteristics for the environment they exist in. They can be found over a range of continents. Biomes are distinct biological communities that have formed in response to a shared physical climate.

5 0

2 years ago

1) How many molecules are there in 985 mL of nitrogen at 0.0° C and 1.00 x 10-6 mm Hg?

RSB [31]

Answer : The number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

Explanation :

First we have to calculate the moles of nitrogen gas by using ideal gas equation.

$PV=nRT$

where,

P = Pressure of $N_2$ gas = $1.00\times 10^{-6}mmHg=1.32\times 10^{-9}atm$ (1 atm = 760 mmHg)

V = Volume of $N_2$ gas = 985 mL = 0.982 L (1 L = 1000 mL)

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $0.0^oC=273+0.0=273K$

Now put all the given values in above equation, we get:

$(1.32\times 10^{-9}atm)\times 0.982L=n\times (0.0821L.atm/mol.K)\times 273K$

$n=5.78\times 10^{-11}mol$

Now we have to calculate the number of molecules present in nitrogen gas.

As we know that 1 mole of substance contains $6.022\times 10^{23}$ number of molecules.

As, 1 mole of $N_2$ gas contains $6.022\times 10^{23}$ number of molecules

So, $5.78\times 10^{-11}$ mole of $N_2$ gas contains $(5.78\times 10^{-11})\times (6.022\times 10^{23})=3.48\times 10^{13}$ number of molecules

Therefore, the number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

8 0

3 years ago

How to calculate density (what’s the formula) <br> density=_ divided by _

Sphinxa [80]

Answer:

density equals weigt divided by volume

Explanation:

$density = \frac{m}{v}$

8 0

3 years ago

The process by which hot and cold air are transferred in the atmosphere is

Elan Coil [88]

Convection: the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.

hope that helps :)

3 0

3 years ago

A salt wedge forms in an estuary because

kherson [118]

Answer:

a rapidly flowing river discharges into the ocean where tidal currents are weak.

Explanation:

The force of the river pushing fresh water out to sea rather than tidal currents transporting seawater upstream determines the water circulation in these estuaries.

6 0

2 years ago