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marissa [1.9K]
3 years ago
11

What is the main factor that prevents the growth of tropical plants in northern part of the United States ?

Chemistry
1 answer:
slamgirl [31]3 years ago
6 0

The main factor that prevents the growth of tropical plants in the northern part of the United States is the climate. The tropical plants require specific conditions to grow and flourish, including warm climate throughout the year, higher precipitation, lots of sunlight. This conditions are lacking in the northern part of the United States where we have smaller amount of sunlight, mostly cloudy sky, and the winters are extremely cold and with lots of snow, and this will contribute to the dying of a tropical plant.

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The arsenic in a 1.223 g sample of a pesticide was converted to H3AsO4 by suitable treatment. The acid was then neutralized, and
Vladimir79 [104]

Answer:

5.471% As₂O₃ in the sample.

Explanation:

<em>...the reaction is: Ag+ + SCN- => AgSCN(s) Calculate the percent As2O3 in the sample. (F.W. As2O3 = 197.84 g/mol).</em>

<em />

First, with the amount of KSCN we can find the moles of Ag in the filtrates. As we know the amount of Ag added we can know the precipitate of Ag and the moles of AsO₄ = 1/2 moles of As₂O₃ in the sample:

<em>Moles KSCN = Moles Ag⁺ in the filtrate:</em>

0.01127L * (0.100mol / L)= 0.001127moles Ag⁺

<em>Total moles Ag⁺:</em>

0.0400L * (0.0781mol/L) = 0.0031564 moles Ag⁺

<em>Moles of Ag⁺ in the precipitate:</em>

0.0031564 - 0.001127 = 0.0020294 moles Ag⁺

<em>Moles AsO₄ = Moles As:</em>

0.0020294 moles Ag⁺ * (1mol As / 3 moles Ag⁺) = 6.765x10⁻⁴ moles AsO₄

<em>Moles As₂O₃:</em>

6.765x10⁻⁴ moles AsO₄ * (1 mol As₂O₃ / 2 mol AsO₄) =

3.382x10⁻⁴ moles As₂O₃

<em>Mass As₂O₃:</em>

3.382x10⁻⁴ moles As₂O₃ * (197.84g/mol) = 0.0669g As₂O₃

Percent is:

0.0669g As₂O₃ / 1.223g sample * 100 =

<h3>5.471% As₂O₃ in the sample</h3>

<em />

7 0
4 years ago
If helium effuses through a porous barrier in 1.34 min, how much time (in min) would it take the same amount of ammonia to effus
timofeeve [1]

Answer:

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

Explanation:

Let the volume of the helium gas be = V

Time taken by the helium gas = t = 1.34 min

Effusion rate of helium gas = R=\frac{V}{1.34 min}

If V volume of ammonia effuse through same porous barrier the effusion rate of ammonia gas will be given as:

R'=\frac{V}{t'}

Using Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

Molar mass of helium gas = M = 4 g/mol

Molar mass of ammonia gas = M' = 17 g/mol

\frac{R}{R'}=\sqrt{\frac{M'}{M}}

\frac{\frac{V}{1.34 min}}{\frac{V}{t'}}=\sqrt{\frac{17 g/mol}{4 g/mol}}

t'=1.34 min\times \sqrt{\frac{17 g/mol}{4 g/mol}}=2.76 min

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

8 0
3 years ago
Which of the following is the only metal that is liquid at room temperature?
otez555 [7]
The answer's D. Mercury
3 0
4 years ago
Read 2 more answers
Describe the three subatomic particles (protons, neutrons, and electrons) in terms of their mass, charge, and location within th
atroni [7]
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protons     1.673*10 ^ - 27 kg        1.6*10 ^ -19 C        in the nucleus
neutrons   1.675*10 ^ - 27 kg        0                             in the nucleus
electron     9.11 * 10 ^ - 31 kg       -1.6 * 10 ^ - 19 C    around the nucleus (orbitals)

Protons and neutrons have almost same masses. Mass of electrons is 1/1840 the mass of the protons.

Protons and electrons have the same magnitud of charge with different sign. Protons are positive and electrons are negative. Neutrons do not have charge.
3 0
3 years ago
In a chemical process, three bottles of a standard fluid are emptied into a larger container. A study of the individual bottles
Setler79 [48]

Answer:

a

The expected value is = 39 units

The standard deviation is = 0.1212 unites

b

The probability is = 0.2047 units

Explanation:

The explanation of this answer is shown on the first uploaded image

5 0
4 years ago
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