Answer:1,152
you have to multiply each side :)
Step-by-step explanation:
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Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.
P (probability) = possible outcomes / total outcomes
It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:
P(A or B) = P(A) + P(B)
All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.
P(1 or 17) = P(1)/18 + P(1)/18
P(1 or 17) = 2/18
Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.
2/18 simplifies to 1/9
So, your answer is 1/9
Answer:
(1/2)
Step-by-step explanation:
From one point, if you go up one and over 2 you will get exactly one block up than from your initial point. And since the graph is pointing down on left side, that means it's positive.
Hi!
Let's divide 4000 by 1000 to see what .1% would be: $4.
Now we multiply 4 by 36 to get 3.6% of 4000: $ 144
Add 4000 and 144 together:40144.
hope this helps!
X+y+z≥627
x=222
y=194
222+194+z≥627
if we solved for z then
z≥221
