Answer:
0.7385 = 73.85% probability that it is indeed a sample of copied work.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Identified as a copy
Event B: Is a copy
Probability of being identified as a copy:
80% of 15%(copy)
100 - 95 = 5% of 100 - 15 = 85%(not a copy). So

Probability of being identified as a copy and being a copy.
80% of 15%. So

What is the probability that it is indeed a sample of copied work?

0.7385 = 73.85% probability that it is indeed a sample of copied work.
X=4
Step 1: Simplify both sides of the equation.
1.5(x+4)-3=4.5(x-2)
(1.5)(x)+(1.5)(4)+ -3 =(4.5)(x)+(4.5)(-2)
(1.5x) + ( 6+-3) =4.5x - 9
(Combine like terms)
1.5x+3=4.5x-9
Step 2: Subtract 4.5x from both sides.
1.5x +3 -4.5x =4.5x=-9-4.5x-3x+3=-9
Step 3: Subtract 3 from both sides.
-3x+3-3=-9-3
-3x=12
Step 4: Divide both by -3
-3x/-3=-12/-3
X=4
The answer is 77 multiply and add them
Answer:
Incorrect
Step-by-step explanation:
This interpretation is incorrect because it states that 98% of the data is with in the confidence interval.
or 98% of the laptop have screen size between 19.2 and 21.4 inches
However, the interpretation would have been correct if it would have stated as - Value of the population mean i.e mean size of the laptop screen lies within the confidence interval.
Are there answer choices or is this an essay?