The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is

Dividing we get,

Adding, we have,

Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,

where
and 
Hence, substituting the values we have,

Dividing, we get,

Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
The answer is 15 units.
Step-by-step explanation:
If you count the number of units from point A up to the same Y coordinate as point B, the amount of units is 9.
Then, the number of units from that point over to point B is 12 units.
Using this information, you can use the Pythagorean theorem to find that 9 squared is 81, 12 squared is 144, add 144 and 81 to get 225, and then you can find the square root of 225 which equals the answer of 15 units.
10% because walking is only 10 percent of the hrs
i believe the answer is 35 dimes and 65 nickels (sorry if i’m wrong lol)