For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
Answer:
Explanation:
mechanical advantage = output force / input force
= 740 N / 55 N
= 13.45
Answer:
-9.8 m/s²
0 m/s
Explanation:
Average acceleration is the change in velocity over change in time.
a = Δv / Δt
a = (-9.8 m/s − 9.8 m/s) / 2.0 s
a = -9.8 m/s²
Average velocity is the change in position over change in time.
v = Δx / Δt
v = (0 m − 0 m) / 2.0 s
v = 0 m/s
Answer : distance, d = 463.7 m
Explanation :
According to the given condition it can be assumed that the first echo would be heard from closest cliff. The second echo is from farther cliff and the third echo is from the reflection between the two cliffs.
Let the distance between the first cliff and the point of firing is x and y is the distance between the second cliff and the point of firing.
Then the first echo will travel 2x distance, second will travel 2y distance and third will travel 2x +2y.
So, using above data :

and

On solving :




x = 321.9 m and y = 141.8 m
Hence, total distance between two cliffs is d = 321.9 m + 141.8 m = 463.7 m