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Aliun [14]
3 years ago
11

What is the function of the labeled structures?

Physics
2 answers:
saveliy_v [14]3 years ago
8 0

Answer:

subject wrong...

option c i guzz...

Marysya12 [62]3 years ago
4 0

Answer:

A: receives information

B: carries information away from the cell body  

C: delivers information to the next cell

Explanation:

i took the quiz!!

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Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr
bixtya [17]
For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
8 0
3 years ago
What is the most abundant element in the universe?<br> A. helium<br> B. hydrogen<br> C. carbon
Naya [18.7K]
The answer is Carbon
3 0
3 years ago
Read 2 more answers
To crack a pecan, you apply a force of 55 N to the nutcracker. The nutcracker applies a force of 740 N to the pecan. What is the
sveticcg [70]

Answer:

Explanation:

mechanical advantage = output force / input force

= 740 N / 55 N

= 13.45

7 0
3 years ago
A ball is thrown straight up at an initial speed of 9.8m/s and, on returning to your hand, hits it moving downward at the same s
likoan [24]

Answer:

-9.8 m/s²

0 m/s

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (-9.8 m/s − 9.8 m/s) / 2.0 s

a = -9.8 m/s²

Average velocity is the change in position over change in time.

v = Δx / Δt

v = (0 m − 0 m) / 2.0 s

v = 0 m/s

3 0
3 years ago
A hunter is standing on flat ground between two vertical cliffs that are directly opposite one another. He is closer to one clif
Ugo [173]

Answer : distance, d = 463.7 m

Explanation :  

According to the given condition it can be assumed that the first echo would be heard from closest cliff. The second echo is from farther cliff and the third echo is from the reflection between the two cliffs.

Let the distance between the first cliff and the point of firing is x and y is the distance between the second cliff and the point of firing.

Then the first echo will travel 2x distance, second will travel 2y distance and third will travel 2x +2y.

So, using above data :

2y=v\times t_3

and

2x=v(t_2+t_3)

On solving :

y=\dfrac{343\times0.827}{2}

y=141.8\ m

x=\frac{343\times(1.05+0.827)}{2}

x=321.9\ m

x = 321.9 m and y = 141.8 m

Hence, total distance between two cliffs is d = 321.9 m + 141.8 m = 463.7 m

7 0
3 years ago
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