To explain, I will use the equations for kinetic and potential energy:

<h3>Potential energy </h3>
Potential energy is the potential an object has to move due to gravity. An object can only have potential energy if 1) <u>gravity is present</u> and 2) <u>it is above the ground at height h</u>. If gravity = 0 or height = 0, there is no potential energy. Example:
An object of 5 kg is sitting on a table 5 meters above the ground on earth (g = 9.8 m/s^2). What is the object's gravitational potential energy? <u>(answer: 5*5*9.8 = 245 J</u>)
(gravitational potential energy is potential energy)
<h3>Kinetic energy</h3>
Kinetic energy is the energy of an object has while in motion. An object can only have kinetic energy if the object has a non-zero velocity (it is moving and not stationary). An example:
An object of 5 kg is moving at 5 m/s. What is the object's kinetic energy? (<u>answer: 5*5 = 25 J</u>)
<h3>Kinetic and Potential Energy</h3>
Sometimes, an object can have both kinetic and potential energy. If an object is moving (kinetic energy) and is above the ground (potential), it will have both. To find the total (mechanical) energy, you can add the kinetic and potential energies together. An example:
An object of 5 kg is moving on a 5 meter table at 10 m/s. What is the objects mechanical (total) energy? (<u>answer: KE = .5(5)(10^2) = 250 J; PE = (5)(9.8)(5) = 245 J; total: 245 + 250 = 495 J</u>)
Answer:

Explanation:
A multistage rock is also known as a step rocket and it is a form of vehicle that can use more than a rocket stage. The rocket stage typically contains propellant as well as its engine. The final speed of the rocket can be estimated using the equation below:

Therefore, the maximum speed of the rocket is 
Answer:
Bulb A has a greater resistance.
Explanation:
Electric power (P) = V²/R
P = V²/R................ Equation 1
Where P = power, V = Voltage, R = Resistance.
Make R the subject of the equation
R = V²/P ................ Equation 2
For Bulb A,
Given: V = 120 V, P = 60 W.
Substitute into equation 2
R = 120²/60
R = 240 Ω
For bulb B
Given: V =120 V, P = 100 W.
Substitute into equation 2
R = 120²/100
R = 14400/100
R = 144 Ω
Hence Bulb A has a greater resistance.
Cheimcal engery is related to positions of atoms within molecules..