Two light bulbs, A and B, are connected to a 120-V outlet (a constant voltage source). Light bulb A is rated at 60 W and light b
1 answer:
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Answer:
(a) Frequency of the standing wave is 614.28 Hz.
(b) Frequency of the standing waves is 1228.56 Hz.
Explanation:
Frequency of standing wave in the case of one end open and other end closed of pipe (also known as stopped pipe) is given by the relation :
.....(1)
Here is the frequency of nth harmonic, v is speed of wave, L is length of the pipe and n is the harmonic which only takes values 1,3,5.. and so on.
(a) Given :
Speed of sound in air, v = 344 m/s
Length of tube, L = 14 cm = 0.14 m
n = 1
Substitute these values in equation (1).
<em>f₁ = </em>614.28 Hz
(b) In this case, half of the tube is filled with water. So,
Length of tube having air, L = (0.14)/2 = 0.07 m
Substitute the suitable values in equation (1).
<em>f₁ = </em>1228.56 Hz
Answer:
Total pressure= 120945[Pa]
Force exerted = 29026800 [N] or 29.02*10^6 [N]
Explanation:
We know that the total pressure is the result of the sum of the atmospheric pressure plus the manometric pressure. The equation is:
In this problem we know the atmospheric pressure 101.325x10^3 [Pa], therefore we need to find the manometric pressure.
The manometric pressure in the bottom of the swimming pool depends only on the water column of water generated (depth of the swimming pool)
where:
density = density of the water 1000 [kg/m^3]
g= gravity [m/s^2]
h= column of water (meters)
replacing the values:
The total pressure will be:
The force exerte on the bottom is defined by the following expression: