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Serggg [28]
3 years ago
10

5. You are skateboarding on top of a small hill and take a break. You have 100 J of potential energy. If

Physics
1 answer:
Sholpan [36]3 years ago
5 0

Given the potential energy of 100 J, the height of the hill is 0.128 m (12.8 cm)

Explanation:

The gravitational potential energy of an object is given by:

U=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the heigth of the object, relative to the ground

In this problem, we have

U = 100 J is the potential energy of the person

g=9.8 m/s^2 is the acceleration of gravity

m = 80 kg is the mass of the person

Solving for h, we find at what height the person is:

h=\frac{U}{mg}=\frac{100}{(80)(9.8)}=0.128 m = 12.8 cm

Learn more about gravitational potential energy here:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

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Block 1 (mass 2.00 kg) is moving rightward at 10.0 m/s and block 2 (mass 5.00 kg) is moving rightward at 3.00 m/s. The surface i
DaniilM [7]

Answer:

a) 0.25m

b) 5 m/s

Explanation:

When the spring is compressed both boxes are moving with the same velocity, so applying the principle of linear momentum conservation:

m1*v_{o1}+m2*v_{o2}=(m1+m2)*v\\v=5m/s

Now applying the principle of energy conservation:

K1+K2+U_{g1}-U_e=Kf+U_{g2}\\K1+0-U_e=K2+0\\U_e=K1+K2-kf\\\frac{1}{2}*k*x^2+=\frac{1}{2}*m1*v1^2+\frac{1}{2}*m1*v1^2-\frac{1}{2}*(m1+m2)*v^2\\\\x=\sqrt{\frac{2.00kg*(10m/s)^2+5.00kg*(3.00m/s)^2-7.00kg*(5m/s)^2}{1120N/m}}\\x=0.25m

We got that the maximum compression is 0.25m.

5 0
3 years ago
CN you help me with this question?
qaws [65]
25% i believe because if were talking 50 percent half it would be 25.


8 0
3 years ago
Which word is not a good way to describe exercise?
Sveta_85 [38]
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3 years ago
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Explanation:

4 0
3 years ago
A piece of plastic with a mass of 15 g is
satela [25.4K]

Answer:

The density of plastic is equal to 0.6 g/mL.

Explanation:

Given that,

The mass of piece of plastic, m = 15 g

It is placed in a graduated cylinder. The water  level in the graduated cylinder rises from  30 mL to 55 mL when the plastic is added.

We need to find the density of plastic.

Rise in volume = 55 mL - 30 mL

= 25 mL

The density of an object is given by :

d=\dfrac{m}{V}\\\\d=\dfrac{15\ g}{25\ mL}\\\\d=0.6\ g/mL

So, the density of plastic is equal to 0.6 g/mL.

5 0
3 years ago
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