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3 years ago

5. You are skateboarding on top of a small hill and take a break. You have 100 J of potential energy. If

Physics

1 answer:

Sholpan [36]3 years ago

5 0

Given the potential energy of 100 J, the height of the hill is 0.128 m (12.8 cm)

Explanation:

The gravitational potential energy of an object is given by:

$U=mgh$

where

m is the mass of the object

g is the acceleration of gravity

h is the heigth of the object, relative to the ground

In this problem, we have

U = 100 J is the potential energy of the person

$g=9.8 m/s^2$ is the acceleration of gravity

m = 80 kg is the mass of the person

Solving for h, we find at what height the person is:

$h=\frac{U}{mg}=\frac{100}{(80)(9.8)}=0.128 m = 12.8 cm$

Learn more about gravitational potential energy here:

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Answer:

The ball doesn't strike the building because it strikes the ground at d=1.62 meters.

Explanation:

V= 5 m/s < 70º

Vx= 1.71 m/s

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h= Vy * t - g * t²/2

clearing t for the flying time of the ball:

t= 0.95 s

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3 years ago

This is a change in an object's position. <br> Net Force<br> Gravitational Pull<br> Motion<br> Force

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Answer:

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3 years ago

a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate <br /&

Katen [24]

Answer:

a) T = 2.26 N, b) v = 1.68 m / s

Explanation:

We use Newton's second law

Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

sin 30 = $\frac{T_x}{T}$

cos 30 = $\frac{T_y}{T}$

Tₓ = T sin 30

T_y = T cos 30

Y axis

T_y -W = 0

T cos 30 = mg (1)

X axis

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they relate it is centripetal

a = v² / r

we substitute

T sin 30 = m $\frac{v^2}{r}$ (2)

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T = $\frac{mg }{cos 30}$

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T = 2.26 N

b) from equation 2

v² = $\frac{T \ sin 30 \ r}{m}$

If we know the length of the string

sin 30 = r / L

r = L sin 30

we substitute

v² = $\frac{ T \ sin 30 \ L \ sin 30}{m}$

v² = $\frac{TL \ sin^2 30}{m}$

For the problem let us take L = 1 m

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v = $\sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }$

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3 years ago

What are potential impacts of pollution on a watershed? Check all that apply.

Studentka2010 [4]

Answer:

contaminated drinking water

deaths of sea creatures that are used as a food source

limits to potential economic activities such as a fishing

Explanation:

A watershed is a large area that comprises of drainage area of all the surrounding water bodies meeting at a common affluence point before draining into sea or ocean or any other large water body. Pollution in this area can pollute the small water streams flowing through it, thereby polluting the larger water body into which it drains.

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2 years ago