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Helen [10]
3 years ago
9

As your rise upwards in the atmosphere, air pressure.

Chemistry
1 answer:
ozzi3 years ago
3 0
Increases. It gets harder to breathe and keep the rhythm.
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Which of the following is NOT true regarding Rutherford's Gold Foil experiment?
erastova [34]

Answer:

The area around the nucleus must be of low mass.

Explanation:

Rutherford`s experiment showed that there are some positive charges in the center of the atoms, and because they are all together, they will give a great mass to the atom.

It was quite different from Thomson`s experiment, in which it was thought that the negative charges were mixed with the positive charges, around the atom (like a Pudding Model). In Rutherford`s experiment, because the direction of beta particles, it was the prediction of the positive nucleus.

Hope this info is useful.

8 0
3 years ago
Name the unit being abbreviated in each measurement (spelling counts). Only write the name of the unit, do not include the numbe
givi [52]

Answer:

Litre (L) , Centimetre (cm) , Kilogram (Kg), Seconds (s) and Kelvin (K)

Explanation:

The units are used for the following measurement;

Litre = Volume

Centimetre = Length

Kilogram = Mass

Seconds = Time

Kelvin = Temperature

5 0
3 years ago
When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6
Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

Explanation:

Wavelength of the photon emitted = \lambda =646.3 nm =646.3\times 10^{-9} m

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

E=\frac{hc}{\lambda }

h = Planck's constant = 6.626\tiomes 10^{-34} Js

c = Speed of the light = 3\times 10^8 m/s

E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}

E=3.07\times 10^{-19} J

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

3 0
4 years ago
Suppose you needed to measure exactly 15.0 mL of water for an
s344n2d4d5 [400]

Answer:

A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.

Explanation:

Hello,

A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.

Best regards.

6 0
3 years ago
Read 2 more answers
BALANCING CHEMICAL EQUATIONS WORKSHEET
kherson [118]

Answer:

Put that in y butt ps

Explanation:

4 0
3 years ago
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