Answer:
ΔG = 98.67 kJ/mol
Explanation:
Let' s consider the following reaction.
Hg₂Cl₂(s) → Hg₂²⁺(aq) + 2Cl⁻(aq)
The standard Gibbs free energy (ΔG°) for the reaction is:
ΔG° = 1 mol × ΔG°f(Hg₂²⁺(aq)) + 2 mol × ΔG°f(Cl⁻(aq)) - 1 mol × ΔG°f(Hg₂Cl₂(s))
where,
ΔG°f: standard Gibbs free energy of formation
ΔG° = 1 mol × (154.72 kJ/mol) + 2 mol × (-134.08 kJ/mol) - 1 mol × (-215.06 kJ/mol)
ΔG° = 101.62 kJ
This is standard Gibbs free energy change per mole of reaction.
The Gibbs free energy of the reaction (ΔG) can be calculated using the following expression.
ΔG = ΔG° - R.T.lnQ
where,
R: ideal gas constant
T: absolute temperature
Q: reaction quotient
ΔG = ΔG° - R.T.ln([Hg₂²⁺].[Cl⁻]²)
ΔG = 101.62 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) . (298.2 K) . ln [(0.926).(0.573)²]
ΔG = 98.67 kJ/mol
I'll just solve it, but you should put each sequence on a separate line please.
C6H12O6 + O2 ===> CO2 + H2O The easiest way to start is to balance the Cs. There are 6 on the left, so you must have 6 on the right.
C6H12O6(s) + O2(g) ===> 6CO2(g) + H2O(l) Next you have to balance out the hydrogens. There are 12 on the left and 2 on the right, so you have to multiply the Hs on the right by 6
C6H12O6(s) + O2(g) ===> 6CO2(g) + 6H2O(l). The Oxygens are the snake in this question. Begin with the right. There are 12 in 6CO2 (6 * 2) = 12 and 6 more on the water (6 * 1) = 6. The total is 12 + 6 = 18
So on the left you have to have a 9 so that 2 * 9 = 18 But 6 of them are already there is the C6H12O6(s) So you need 12 more from the oxygen. 6*12 = 12
C6H12O6(s) + 6O2(g) ===> 6CO2(g) + 6H2O(l)
And it is complete.
The answer should be A I think. But it doesn't look right. It should be 1 6 6 6
Answer:
um Im not sure what the heck that is
Answer:
This molecule can either be named methoxyethane (since the longest chain is 2C so ethane, and it has a OCH3 group attached which we call methoxy). Or it can be named ethyl methyl ether (since there is a methyl group and an ethyl group attached to the oxygen in the center.
Explanation:
Ethers are compounds having two alkyl or aryl groups bonded to an oxygen atom, as in the formula R1–O–R2. The ether functional group does not have a characteristic IUPAC nomenclature suffix, so it is necessary to designate it as a substituent.
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