Answer:
The work done and heat absorbed are both -8,1 kJ
Explanation:
The work done in an isobaric process is defined as:
W = -P (Vf - Vi)
Where P is pressure ( 10 atm)
Vf = 10 L
Vi = 2 L
Thus, <em>W = -80 atm×L ≡ -8,1 kJ</em>
This is the work done in expansion of the gas. As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.
I hope it helps!
Moles = Molarity x Volume
Moles = 2.0 x 0.50
= 1.0 mole
hope this helps!
Answer : Density of any particular matter remains the same at any concentration at any weight.
Density does not varies with the concentration. The formula for density is mass / volume.
So if the mass changes the density will change accordingly, also if the volume changes the density will get changed.
because, of the above reasons density is referred as a characteristic property of matter.
