Luster is the correct answer.
Answer : The metal used was iron (the specific heat capacity is
).
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-q_2](https://tex.z-dn.net/?f=q_1%3D-q_2)
![m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-m_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29)
where,
= specific heat of unknown metal = ?
= specific heat of water = ![4.184J/g^oC](https://tex.z-dn.net/?f=4.184J%2Fg%5EoC)
= mass of unknown metal = 150 g
= mass of water = 200 g
= final temperature of water = ![34.3^oC](https://tex.z-dn.net/?f=34.3%5EoC)
= initial temperature of unknown metal = ![150.0^oC](https://tex.z-dn.net/?f=150.0%5EoC)
= initial temperature of water = ![25.0^oC](https://tex.z-dn.net/?f=25.0%5EoC)
Now put all the given values in the above formula, we get
![150g\times c_1\times (34.3-150.0)^oC=-200g\times 4.184J/g^oC\times (34.3-25.0)^oC](https://tex.z-dn.net/?f=150g%5Ctimes%20c_1%5Ctimes%20%2834.3-150.0%29%5EoC%3D-200g%5Ctimes%204.184J%2Fg%5EoC%5Ctimes%20%2834.3-25.0%29%5EoC)
![c_1=0.449J/g^oC](https://tex.z-dn.net/?f=c_1%3D0.449J%2Fg%5EoC)
Form the value of specific heat of unknown metal, we conclude that the metal used in this was iron (Fe).
Therefore, the metal used was iron (the specific heat capacity is
).
the answer is true the first one
Answer:
The answer to your question is 1.51 moles of PBr₃
Explanation:
Data
moles of Br = 2.27
moles of PBr₃ = x
Balanced chemical reaction
2P + 3Br₂ ⇒ 2PBr₃
Reactant Element Products
2 P 2
6 Br 6
-Use proportions to find the answer
3 moles of Br₂ ------------------ 2 moles of PBr₃
2.27 moles of Br₂ ------------------ x
x = (2.27 x 2) / 3
x = 4.54 / 3
x = 1.51 moles
Answer:
Carbonates are widely used in industry, such as in iron smelting, as a raw material for Portland cement and lime manufacture, in the composition of ceramic glazes, and more.