Answer:
85.34g of NH3
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
N2 + 3H2 —> 2NH3
Step 2:
Determination of the number of moles of NH3 produced by the reaction of 2.51 moles of N2. This is illustrated below:
From the balanced equation above,
1 mole of N2 reacted to produce 2 moles of NH3.
Therefore, 2.51 moles of N2 will react to produce = (2.51 x 2)/1 = 5.02 moles of NH3.
Therefore, 5.02 moles of NH3 is produced from the reaction.
Step 3:
Conversion of 5.02 moles of NH3 to grams. This is illustrated below:
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Number of mole of NH3 = 5.02 moles
Mass of NH3 =..?
Mass = mole x molar Mass
Mass of NH3 = 5.02 x 17
Mass of NH3 = 85.34g
Therefore, 85.34g of NH3 is produced.
The answer is caso4 and ca(C2H3O2)2
Due to it's electronic configuration w/c is 1s2 2s2 2ps 3s1 considering the last w/c is 3s1, sodium should be in row 3 period a1.
Explanation:
i think right one is c.
it is because proton is different in each element.
Answer:
Observe odor, determine pH, determine density, determine boiling point
Explanation:
The correct procedures that would be best to use to determine whether a beaker contains only distilled water would be to observe the odor of the liquid in the beaker, determine the pH of the liquid, determine the density, and then determine the boiling point of the liquid.
<em>Water is generally odorless and has a pH of approximately 7 with a density of 1 kg/m3 and a boiling point of 100 </em>
<em>. If the liquid in the beaker ticks all these conditions, then it can be established to be only distilled water.</em>