Explanation:
The given data is as follows.
Mass of apple sauce mixture = 454 kg
Heat added (Q) = 121300 kJ
Heat capacity (
) of apple sauce at 
= 4.0177 
So, Heat given by heat exchanger = heat taken by apple sauce
Q = 
or, Q = 
Putting the given values into the above formula as follows.
Q =
121300 kJ = 
= 
Thus, we can conclude that outlet temperature of the apple sauce is .
Answer:
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Answer:
reproduction
Explanation:
reproduction, process by which organisms replicate themselves
Arrhenius' Law relates activation energy, Ea, rate constant, K, and temperature, T as per this equation:
K (T) = A * e ^ (-Ea / RT), where R is the universal constant of gases and A is a constant which accounts for collision frequency..
Then you can find the ration between K's at two different temperatures as:
K1 = A * e ^ (-Ea / RT1)
K2 = A* e ^(-Ea / RT2)
=> K1 / K2 = e ^ { (-Ea / RT1) - Ea / RT2) }
=> K1 / K2 = e ^ {(-Ea/ R ) *( 1 / T1 - 1 T2) }
=> K1 / K2 = e^ { (-205,000 j/mol / 8.314 j/mol*k )* ( 1 / 505K - 1/ 485K) }
=> K1 / K2 = e ^ (2.0134494) ≈ 7.5
Answer: 7.5
