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3 years ago

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Physics

1 answer:

Darina [25.2K]3 years ago

4 0

Resolving vectors question. See diagram enclosed.

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Please help with a simple Physics question!

zheka24 [161]

Compression- a region in a longitudinal (sound) wave where the particles are closest together. Rarefaction- a region in a longitudinal (sound) wave where the particles are furthest apart. Wave motion and particles.

Answer is B.

6 0

3 years ago

A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5

Alborosie

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Substituting into the equation, we have;

$S =20*5 + \frac{1}{2}*(-4)*5^{2}$

$S =100 + (-2)*25$

$S =100 - 50$

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

$V^{2} = U^{2} + 2aS$

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

$V^{2} = 20^{2} + 2(-4)*50$

$V^{2} = 400 - 400$

$V^{2} = 0$

V = 0m/s

Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.

5 0

3 years ago

PLEASE HELP! QUESTION 2A,B and C. PLEASE HELP. 50 points

Greeley [361]

Answer:

first

Explanation:

7 0

3 years ago

Elect the correct equations that show that when a 3.0-kg book is lifted 2.6 m its increase in gravitational potential energy is

grigory [225]

The increase in gravitational potential energy for an object of mass m is given by
$\Delta U = mg \Delta h$
where $\Delta h$ is the increase in altitude of the object.

In our problem, m=3.0 kg, $\Delta h= 2.6 m$ and $g=10 m/s^2$ (approximated value), so we have
$\Delta U = mg\Delta h=(3.0 kg)(10 m/s^2)(2.6 m)=78 J$

5 0

3 years ago

When operated on a household 110.0-V line, typical hair dryers draw about 1650 W of power. We can model the current as a long st

defon

Answer:

Current in the hair dryer will be equal to 15 A

Explanation:

We have given that household is operated at 110 volt

So potential difference V =110 volt

Power drawn by hairdryer is P = 1650 watt

We have to find the current in the hair dryer

We know that power is given as P = VI, here V is potential difference and I is current

So $1650=110\times I$

I = 15 A

So current in the hair dryer will be equal to 15 A

4 0

4 years ago