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djyliett [7]
3 years ago
9

How would the atmosphere of earth differ if the earth was much larger

Physics
2 answers:
Tcecarenko [31]3 years ago
7 0
It would most likely be harder to breathe and we would probably not get enough sun
Juli2301 [7.4K]3 years ago
4 0
If the earth just doubles its size in an instant, the oxygen present in the atmosphere could be much larger. Due to these, we could theorize that insects could grow much larger because the size of their body is heavily dependent on the maximum amount of oxygen present in the atmosphere. Air pressure also increases thus those aerial enthusiasts would enjoy their professions.
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A ball is rolling down a hill. Wich action would slow the ball down?
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Answer:

Friction Force

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Explanation:

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What is the thermal energy of an object?
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Which of the following would decrease the resistance to the flow of an electric current through a body?
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If I rub a polythene piece with a wool , is there a transfer of mass from wool to polythene?​
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8 0
3 years ago
A physics professor demonstrates the Doppler effect by tying a 600 Hz sound generator to a 1.0-m-long rope and whirling it aroun
VARVARA [1.3K]

Answer:

(a) f= 622.79 Hz

(b) f= 578.82 Hz

Explanation:

Given Data

Frequency= 600 Hz

Distance=1.0 m

n=120 rpm

Temperature =20 degree

Before solve this problem we need to find The sound generator moves on a circular with tangential velocity

So

Speed of sound is given by

c = √(γ·R·T/M) ............in an ideal gas

where γ heat capacity ratio

R universal gas constant

T absolute temperature

M molar mass

The speed of sound at 20°C is

c = √(1.40 ×8.314472J/molK ×293.15K  / 0.0289645kg/mol)

c= 343.24m/s

The sound moves on a circular with tangential velocity

vt = ω·r.................where   ω=2·π·n

vt= 2·π·n·r

vt= 2·π · 120min⁻¹ · 1m

vt= 753.6 m/min  

convert m/min to m/sec

vt= 12.56 m/s

Part A

For maximum frequency is observed  

v = vt

f = f₀/(1 - vt/c )

f= 600Hz / (1 - (12.56m/s / 343.24m/s) )  

f= 622.789 Hz

Part B

For minimum frequency is observed

v = -vt

f = f₀/(1 + vt/c )

f= 600Hz / (1 + (12.56m/s / 343.24m/s) )

f= 578.82 Hz

3 0
2 years ago
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