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djyliett [7]
4 years ago
9

How would the atmosphere of earth differ if the earth was much larger

Physics
2 answers:
Tcecarenko [31]4 years ago
7 0
It would most likely be harder to breathe and we would probably not get enough sun
Juli2301 [7.4K]4 years ago
4 0
If the earth just doubles its size in an instant, the oxygen present in the atmosphere could be much larger. Due to these, we could theorize that insects could grow much larger because the size of their body is heavily dependent on the maximum amount of oxygen present in the atmosphere. Air pressure also increases thus those aerial enthusiasts would enjoy their professions.
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The fluid pressure 10 ft underwater is ____ the fluid pressure 5 ft underwater
quester [9]
5ft is two times the 10ft
5 0
3 years ago
If the fly experienced a force of 100 N when it hits how big was the force on the vehicle in this collision
iogann1982 [59]

Answer:

100N

Explanation:

because newton's third law of motion states that if body A exerts a force on the body B, then Body B will exert an equal force but opposite in direction force on body A

so if the fly experienced 100N, then the car will also experience 100N

hope you get it

please mark

8 0
3 years ago
There are four springs stretched by the same mass. Spring A stretches 25 cm. Spring B stretches 10 cm. Spring C stretches 100 cm
saul85 [17]

Answer:

spring D stretches the weakest

6 0
2 years ago
A book is on the table. If the weight of the book is 25 newtons, what is the magnitude and direction of the normal force?
Andrej [43]
I'm not sure about the magnitude, but the direction of the normal force is upward. 
4 0
3 years ago
Read 2 more answers
A golf ball has a mass of 120g. Calculate its increase in mass when it is travelling at 40ms1. What is this as a percentage of i
kicyunya [14]

Answer:

Percentage=8.889\times 10^{-13}%

Explanation:

From special theory of relativity the dynamic mass m is related with the rest mass m_{0}of the body as

m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }

Here, c is the speed of light and v is the velocity of object.

Given mass of the golf ball is 120 g.

m=\frac{120 }{\sqrt{1-\frac{(40)^{2} }{(3\times 10^{8} )^{2} } } }\\m=120(1-\frac{(40)^{2} }{(3\times 10^{8}) ^{2} })^{-\frac{1}{2} } \\

Now applying the binomial theorem and solve the above equation.

m=(1+\frac{1}{2}(\frac{40}{3\times 10^{8} }) ^{2} )\\m=120(1+8.889\times 10^{-15})

Therefore, increase in mass is,

\Delta m=120\times 8.889\times 10^{-15} \\\Delta m=10.6668\times 10^{-13} g

Now percentage of increase in mass with rest mass is,

Percentage=\frac{10.6668\times 10^{-13} g}{120g} \times 100\\Percentage=8.889\times 10^{-13}

Therefore, the percentage of increase in mass with rest mass is Percentage=8.889\times 10^{-13}.

4 0
4 years ago
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