11.625 moles of Na₂O are produced.
<h3>What do you mean by the term mole ?</h3>
A mole is defined as the amount of a substance that contains exactly 6.02214076 × 10²³ ‘elementary entities’ of the given substance.
It can be represented by the following formula:
n = N/NA
To calculate moles of Na₂ O produced are -:
40 gm of sodium
3.00 gm of oxygen
4 Na+ O₂----->2Na₂O
First calculate limiting reagent,
Stochiometric ratio,
a/b=4/1
=4
Molar ratio,
M/n=4/22/3/22=4/22×32/3
=1.93
As a/b>m/n
So, sodium is limiting reagent
4 Na+ O₂----->2Na₂O
As 32 g of O₂ produced =124 g of Na₂O
SO,
3 gm of O₂ produced =124×3/32
=11.625 gm
11.625 gm of Na₂O can be produced .
Learn more about mole ,here:
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Explanation:
Here are the answers. Do note that I had to convert the enthalpy to joules and temperature to Kelvin to make the unit for entropy work out.
Answer: 
and 
and 
and 
and 
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
For the given chemical equations:
1. 
Here, is loosing a proton, thus it is considered as an acid and after losing a proton, it forms which is a conjugate base.
2. 
Here, is loosing a proton, thus it is considered as an acid and after losing a proton, it forms 
which is a conjugate base.
3. 
Here, is loosing a proton, thus it is considered as an acid and after losing a proton, it forms which is a conjugate base.
4. 
and 
are not conjugate acid/ base pairs.
5. 
Here, is loosing a proton, thus it is considered as an acid and after losing a proton, it forms which is a conjugate base.
When solid ammonium nitrate is dissolved in water, it becomes completely dissociated and separates into the two ions, ammonium and nitrate. This forms a homogeneous solution, which is a mixture that has the same appearance and composition throughout. The reaction that takes place is shown below:
H₂O
NH₄NO₃₍s₎ --→ NH₄⁺ ₍aq₎ + NO₃⁻ ₍aq₎
