So,
With addition, we the last digit we keep will be the one which is known for both individual values.
We know 2.13 to the hundredths, but we only know 1 to the ones. Therefore, we will round off in the ones place.
2.13 + 1 = 3.13 (unrounded)
= 3 (rounded)
Hope this helps!
Answer: 149
Explanation:
Using the ideal gas equation; PV = nRT
P= Pressure = 0.910 atm, T= Temperature = ?
V= Volume = 4.0L R = Gas constant = 0.08206 L.atm/mol/K
n = number of moles = 0.297
Making 'T' the subject of the formular, we have;
T = P V/ n R = 0.910 x 4 / 0.297 x 0.08206
= 149
Answer:
Liming reagent in the given reaction is oxygen.
Explanation:
Mass of octane = 12.85 g
Mass of oxygen = 7.46 g
Molar mass of octane = 114.23 g/mol
Molar mass of oxygen = 32
According to the reaction, 2 moles of octane requires 25 moles of O2
so, 0.1125 moles of octane requires 
of oxygen.
but only 0.2331 mol of oxygen is present.
Hence, oxygen is the limiting reagent
