O2 gas, where there are two Oxygen atoms which are covalently bonded together
<u>Answers:</u>
a. 131.85 grams
b. 134.69 grams
To calculate the number of grams in the number of moles given for each compound, consider the formula:
<em>Moles = No. of grams / molar mass</em>
Therefore, to find the gram it will become:
<em>No. of grams = moles x molar mass</em>
a. 0.410 mol of NaCl (sodium chloride)
Molar mass of NaCl = (286.14 + 35.45) = 321.59
No. of grams = moles x molar mass
No. of grams = 0.410 x 321.59 = 131.85 grams
b. 4.80 mol of C2H4 (ethylene)
Molar mass of C2H4 = (12.01 x 2) + (1.01 x 4) = 28.06
No. of grams = moles x molar mass
No. of grams = 4.80 x 28.06 = 134.69 grams
Answer:
Decreasing the volume of solvent in the solution of molecule A
Explanation:
We know that one of the factors that affect the rate of reaction is the concentration of the reactants. The greater the concentration of reactants, the faster the rate of reaction (the greater the frequency of collision between reactants).
Hence, when we decrease the volume of solvent in the solution of molecule A, the concentration of the solution increases and consequently more particles of molecule A are available to collide with particles of molecule B resulting in a higher rate of reaction.
I think it is 1620 (lxwxh) x 10 to get to millimeters
C. quadruples the rate
<h3>Further explanation</h3>
Given
The rate law :
R=k[A]²
Required
The rate
Solution
There are several factors that influence reaction kinetics :
- 1. Concentration
- 2. Surface area
- 3. Temperature
- 4. Catalyst
- 5. Pressure
- 6. Stirring
The rate is proportional to the concentration.
If the concentration increased, the reaction rate will increase
The reaction is second-order overall(The exponent is 2)
The concentration of A is doubled, the reaction rate will increase :
r = k[A]² ⇒ r= k[2A]²⇒r=4k[A]²
<em>The reaction rate will quadruple.</em>
