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Tema [17]
3 years ago
7

Elements and molecules will always reemit the exact radiation that they

Chemistry
1 answer:
SashulF [63]3 years ago
4 0
Elements/molecules will absorb a photon if energy, which will put them into an excited state. They will then emit that same energy back in order to come back down to their ground state energy.
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Which of the following terms is a term that could refer to heterogeneous matter? a. element b. mixture c. compound d. solution
kupik [55]

Answer : b. mixture

<h3>Further explanation</h3>

Element and compound are included in pure substance where the composition is the same in each part

Elements are made up of 1 type of atom, while the compounds of 2 or more types of atoms , both can be represented in the form of chemical symbols

A mixture is a combination of substances. The properties of a substance in the mixture component are unchanged

The mixture can be a homogeneous mixture or a heterogeneous mixture

  • the homogeneous mixture if each part has the same composition
  • the heterogeneous mixture if each part has a different composition

Solution including into Homogeneous mixture, while suspension into a heterogeneous mixture

So a term that could refer to heterogeneous matter : b. mixture

6 0
3 years ago
Which unit is not a measurement of volume?<br><br> cm<br> L<br> ml<br> cm3
Xelga [282]

Which unit is not a measurement of volume?

<u>cm </u>

L

ml

cm³

Cm is a measurement for length

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4 years ago
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In your own words, explain the process of how blood circulates through the body to supply oxygen, nutrients and remove waste. (W
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Blood circulation is what our body runs off. If we don’t have this nutrition is not delivered to certain parts of the human body this nutrients are used to keep the body moving and healthy!
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How does the nucleus control cellular activity?
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3 0
3 years ago
Ethanol is a possible fuel. Use average bond energies to calculate ΔHrxn for the combustion of ethanol. CH3CH2OH(g) + 3 O2(g) →
Maksim231197 [3]

Explanation:

The reaction is as follows.

       CH_{3}CH_{2}OH(g) + 3O_{2}(g) \rightarrow 2CO_{2} + 3H_{2}O(g)

Standard values of bond energies are as follows.

C-C = 347 kJ/mol

C-H = 414 kJ/mol

C-O = 360 kJ/mol

O-H = 464 kJ/mol

O=O = 498 kJ/mol

C=O = 799 kJ/mol

Hence, calculate the change in enthalpy of the reaction as follows.

 \Delta H_{rxn} = \sum \text{bond energy of reactants} - \sum \text{bond energy of products}

= [5(C-H) + 1(C-C) + 1(C-O) + 1(O-H) + 3(O=O)] - [4(C=O) + 6(O-H)]

 = [5 \times 414 + 1 \times 347 + 1 \times 360 + 1 \times 464 + 3 \times 498] kJ - [4 \times 799 + 6 \times 464]kJ

       = (4735 - 5980) kJ

       = -1245 kJ

Thus, we can conclude that the enthalpy of given reaction is -1245 kJ.

3 0
3 years ago
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