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3 years ago

Steel: Propane: Calcium chloride: Water:

Chemistry

2 answers:

kirill [66]3 years ago

8 0

Answer:

Steel is a metallic bond

Propane is a covalent bond

Calcium Chloride is an Ionic Bond

Water is a covalent bond

Explanation:

ence a material's properties, identify each of the , ionic, covalent, or metallic bonds

Ionic Bonds are where the extra outer electron of one atom transfers to the other atom.

Covalent Bonds are where the outer electron of one atom takes the open path to the nucleus (negative valance) of a 2nd atom.

Metallic Bonds are formed from the attraction between free electrons and fixed positively charged metallic atoms. Metallic bonds extend over the entire molecular structure.

Substance Properties

Steel Conducts electricity as solid and liquid

Propane Low melting point

Calcium Chloride Conducts electricity when dissolved in water

Water Solid form is brittle, melts at 0C

Steel is an alloy of carbon, iron and other things

Propane = C3H8 C4- H+

Calcium Chloride = CaCl2 = Ca2+ Cl-

Water = H2O = OH- and H+

kondor19780726 [428]3 years ago

4 0

What is the question

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Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

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i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant = $5.12^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (benzene)= 1480 g =1.48 kg

Molar mass of solute (octane) = 114.0 g/mol

Mass of solute (octane) = 220 g

$(5.50-T_f)^0C=1\times 5.12\times \frac{220g}{114.0 g/mol\times 1.48kg}$

$(5.50-T_f)^0C=6.68$

$T_f=-1.16^0C$

Thus the freezing point of a solution will be $-1.16^0C$

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The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this

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Explanation:

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For a hypothetical reaction:

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