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ki77a [65]
3 years ago
7

Steel: Propane: Calcium chloride: Water:

Chemistry
2 answers:
kirill [66]3 years ago
8 0

Answer:

Steel is a metallic bond

Propane is a covalent bond

Calcium Chloride is an Ionic Bond

Water is a covalent bond

Explanation:

ence a material's properties, identify each of the , ionic, covalent, or metallic bonds

Ionic Bonds are where the extra outer electron of one atom transfers to the other atom.

Covalent Bonds are where the outer electron of one atom takes the open path to the nucleus (negative valance) of a 2nd atom.

Metallic Bonds are formed from the attraction between free electrons and fixed positively charged metallic atoms. Metallic bonds extend over the entire molecular structure.

Substance                  Properties

Steel                           Conducts electricity as solid and liquid

Propane                      Low melting point

Calcium Chloride       Conducts electricity when dissolved in water

Water                          Solid form is brittle, melts at 0C

Steel is an alloy of carbon, iron and other things

Propane = C3H8 C4- H+

Calcium Chloride  = CaCl2 = Ca2+ Cl-

Water = H2O = OH- and H+

kondor19780726 [428]3 years ago
4 0
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The coefficient of thermal expansion α = (1/V)(∂V/∂T)p. Using the equation of state, compute the value of α for an ideal gas. Th
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The coefficient of thermal expansion α is  

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From the question we are told that

   The  coefficient of thermal expansion is \alpha  =  \frac{1}{V} *  (\frac{\delta V}{ \delta  P})  P

    The coefficient of compressibility is \beta  =  - (\frac{1}{V} ) *  (\frac{\delta V}{ \delta P} ) T

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       \frac{\delta V}{\delta T }  =  \frac{ n R }{P}

substituting the equation above into \alpha

       \alpha  =  \frac{1}{V} *  ( \frac{ n R }{P})  P

        \alpha  = \frac{nR}{PV}

Recall from ideal gas equation  T =  \frac{PV}{nR}

So

          \alpha  =  \frac{1}{T}

Now differentiate equation (1) above with respect to  P  at constant T

          \frac{\delta  V}{ \delta P}  =  -\frac{nRT}{P^2}

substituting the above  equation into equation of \beta

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        \beta =\frac{ (\frac{n RT}{PV} )}{P}

Recall from ideal gas equation that

       \frac{PV}{nRT}  =  1

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Now  considering (\frac{ \delta P }{\delta  T} )V

From equation (1) we have that

       \frac{ \delta P}{\delta  T}  =  \frac{n R }{V}

From  ideal equation

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So

     \frac{\delta P}{\delta  T}  =  \frac{PV}{TV}

=>  \frac{\delta  P}{\delta  T}  =  \frac{P}{T}

=>   \frac{\delta  P}{\delta  T}  =  \frac{\alpha }{\beta}

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