Answer: 0.306
Explanation:
from the question we are given the following
mass of sled (m) = 50 kg
force (f) = 1.75 x 10^2 N = 175 N
distance (s) = 6 m
net work done on the sled = 1.50 x 10 ^2 N = 150 N
acceleration due to gravity (g) = 9.8 m/s^2
coefficient of friction = μ
lets first calculate the frictional force (ff)
ff = μ x m x g = μ x 50 x 9.8 = 490 μ
work done on the slide by the applied force (W1)= f x s = 175 x 6 = 1050 j
work done on the slide by frictional force (W2) = ff x s = 490 μ x 6 = 2940μ j
now the net work done is the work done by the frictional force subtracted from the work done by the applied force
net work done = W1 - W2
150 = 1050 - 2940μ
2940μ = 1050 - 150
μ = 900 / 2940
μ = 0.306
Our eyes detect light only within a range of frequencies called visible light.
Explanation:
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Answer:
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Explanation:
<em>In a class, the teacher asked a student named Mary to mark America on the Globe. Mary did it correctly, now the teacher asked the students "Who found America?" </em>
<em> The students replied.....</em>
<h2>Ma'am Mary found America! </h2>
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Newton's law of universal gravitation:
F = GMm/r²
F = gravitational force, G = gravitational constant, M and m are the masses, r = distance between the masses
Given values:
F = 4.24×10⁻¹⁰N, G = 6.67×10⁻¹¹Nm²kg⁻², M = m = 29kg
Plug in and solve for r:
4.24×10⁻¹⁰ = 6.67×10⁻¹¹(29)(29)/r²
r = 11.5m